Python如何生成无括号、逗号、空格的连续字符串变量？

你当前代码生成的是元组（用逗号分隔的元素包裹在括号里），所以打印时会出现括号、逗号和空格。要得到连续的字符串，需要把各个字符拼接起来，以下是两种可行方案：

方案1：直接用+拼接字符串 #

把生成元组的代码改成字符串相加，每个元素直接用+连接：

Word = Letters[FirstLetter] + SecondLetter + ThirdLetter + FourthLetter + Letters[Endletter]

方案2：用str.join()方法（更高效） #

把所有需要拼接的字符放到一个可迭代对象（比如列表）中，用空字符串''来连接：

Word = ''.join([Letters[FirstLetter], SecondLetter, ThirdLetter, FourthLetter, Letters[Endletter]])

修改后的完整代码示例 #

Letters = ["u", "i", "p","a","o","g", "h","j","k","l","z","x","v","b"]

FirstLetter = -1
SecondLetter = 'o'
ThirdLetter = 'a'
FourthLetter = 'l'
Endletter = 0
while FirstLetter < 13:
    FirstLetter = FirstLetter +1
    # 这里用方案1的写法，也可以替换成方案2的代码
    Word = Letters[FirstLetter] + SecondLetter + ThirdLetter + FourthLetter + Letters[Endletter]
    print(Word)

运行后第一行输出就是uoalu，完全符合你的需求。

内容的提问来源于stack exchange，提问作者DiscoPy