TypeScript中用正则分割数学表达式字符串遇空元素问题求助

The empty strings in your split result come from split() capturing the gaps between adjacent matched characters (like between - and () or before the first match. Instead of fighting with split(), using match() is a more straightforward way to get exactly the tokens you want.

Here's the regex to use with match():

const formula = '1+2-(0.67*2)/2%2=O_AnnualSalary';
const tokens = formula.match(/[a-zA-Z_][a-zA-Z0-9_]+|[0-9]|[+\-*/%()=.]/g);

What this regex does: #

• [a-zA-Z_][a-zA-Z0-9_]+: Grabs identifiers like O_AnnualSalary (starts with letter/underscore, followed by letters, numbers, or underscores) as single tokens.
• [0-9]: Captures individual digits (0-9) as separate tokens.
• [+\-*/%()=.]: Matches each operator, parenthesis, decimal point, or equals sign as its own token.

Running this will give you your expected output:

['1', '+', '2', '-', '(', '0', '.', '6', '7', '*', '2', ')', '/', '2', '%', '2', '=', 'O_AnnualSalary']

If you want to stick with split(): #

Just filter out the empty strings after splitting:

const tokens = this.createdFormula.split(/([?=+-*/%,()])/).filter(token => token !== '');

This removes the unwanted empty entries while keeping all valid tokens.

内容的提问来源于stack exchange，提问作者Vaibhav Mandlik