如何在create_game请求的data键中正确传递userName变量？

问题根源 #

从实际发送的create_game请求内容可见，data字段中的username参数值被嵌套了双引号（username="673508846384"），导致URL参数格式错误；同时原请求模板中username字段存在语法缺失（少了开头的双引号）。

解决步骤 #

• 清理变量值：从登录响应的playerName提取值时，确保存储的是不带双引号的纯字符串（比如直接存673508846384，而非带引号的"673508846384"）。
• 修正请求模板语法：
  1. 修复username字段的语法错误，原模板中"username": ${userName}",应改为"username": "${userName}",，补上开头的双引号。
  2. 修改data字段中的参数模板，因为URL参数不需要给值加引号，直接写成&username=${userName}即可。

修正后的create_game请求模板示例 #

42[
"create_game",
{
"key": "AUEEW891WL",
"socketId":"${sid}",
"username": "${userName}",
"avatar": "avatar17.jpg",
"language": "en",
"playerMove": "",
"joinGame": "",
"replay": 0,
"gameID": 0,
"gameNo": 0,
"data": "&gameID=undefined&game=texas&playMoney=1&gameStyle=private-cashgame&tableName=llkTable${counter1}&rakeRate=0&speed=60&sb=10&bb=20&tablelow=100&tablelimit=1000&videorequired=false&username=${userName}",
"players": 0,
"level": 347,
"lastAction": "",
"game": "",
"playMoney": 1,
"role": "1",
"token":"${token}",
"playerId":"${playerId}"
}
]

修正后实际发送的正确内容示例 #

42[
"create_game",
{
"key": "AUEEW891WL",
"socketId":"TRV8Rm_jtsqn_BBFAAiM",
"username": "673508846384",
"avatar": "avatar17.jpg",
"language": "en",
"playerMove": "",
"joinGame": "",
"replay": 0,
"gameID": 0,
"gameNo": 0,
"data": "&gameID=undefined&game=texas&playMoney=1&gameStyle=private-cashgame&tableName=llkTable47&rakeRate=0&speed=60&sb=10&bb=20&tablelow=100&tablelimit=1000&videorequired=false&username=673508846384",
"players": 0,
"level": 347,
"lastAction": "",
"game": "",
"playMoney": 1,
"role": "1",
"token":"0a5260592b6efc02d3102c639eac0f60d91ad7de8bf57fa114da179f05bcfa84",
"playerId":"25601"
}
]

内容的提问来源于stack exchange，提问作者Kavita