如何在Bash/Shell脚本中用Sed删除路径指定重复单词后的内容？

Got it, let's first figure out why your current sed command isn't working as expected. The sed 's/config.*//' uses greedy matching—it grabs the first occurrence of "config" and everything that follows (including the second "config" in the filename), which is why you end up with /opt/xyz/ instead of the desired /opt/xyz/config/.

Here are a few reliable solutions to get the directory path you want:

Solution 1: Strip the Final Filename (Universal for Any File) #

This method works no matter what the filename is—it removes everything after the last forward slash:

echo "/opt/xyz/config/config.xml" | sed 's/[^/]*$//'

How it works: #

• [^/]* matches any sequence of characters that aren't a forward slash
• $ anchors the match to the end of the line
• Replacing this match with an empty string deletes the filename, leaving you with /opt/xyz/config/

Solution 2: Target the Exact Filename #

If you only need to handle config.xml specifically, use a precise pattern to remove just that filename:

echo "/opt/xyz/config/config.xml" | sed 's/config\.xml$//'

How it works: #

• config\.xml matches the exact filename (we escape the . with a backslash because . in regex matches any single character)
• $ ensures we only match it at the end of the line
• This replaces config.xml with nothing, preserving the parent directory path.

Solution 3: Non-Greedy Matching (GNU Sed Only) #

If you're using GNU sed (common on Linux systems), you can use non-greedy matching to stop at the shortest possible match after "config":

echo "/opt/xyz/config/config.xml" | sed -E 's/config.*?\.xml$//'

How it works: #

• -E enables extended regular expressions
• .*? is the non-greedy version of .*—it matches the shortest sequence instead of the longest
• This ensures we only target the "config" in the filename, leaving the directory's "config" intact.

All three methods will give you the /opt/xyz/config/ output you're looking for. The first solution is the most flexible if you need to handle different filenames in the same directory structure.

内容的提问来源于stack exchange，提问作者Aashlesh Dhumane