如何将带调用的require语句转换为ES6的import语法?
require('url-unshort')() to ES6 Modules Great question! Let's unpack what's going on here and how to convert this CommonJS syntax to proper ES6 modules.
Why the original syntax works
The line const uu = require('url-unshort')() tells us the url-unshort module exports a factory function—not the ready-to-use utility object directly. When you run require('url-unshort'), you retrieve that factory function, and the trailing () immediately calls it to initialize and return the actual uu object you'll use for expanding short URLs.
ES6 Module Conversion Options
Since ES6 modules handle exports differently, here are two reliable ways to replicate this behavior:
Option 1: Default Import + Immediate Invocation
This is the cleanest approach, as we directly import the factory function (which is the module's default export) and call it:
// Import the factory function import urlUnshortFactory from 'url-unshort'; // Invoke it to get the initialized utility object const uu = urlUnshortFactory(); // Use it just like before uu.expand('https://bit.ly/example') .then(longUrl => console.log('Expanded URL:', longUrl)) .catch(err => console.error('Error expanding URL:', err));
Option 2: Using import * as (if you prefer this style)
If you use import * as, you'll get an object containing all exports from the module. The factory function will be under the default property, so you'll need to call that:
// Import all exports into a module object import * as urlUnshortModule from 'url-unshort'; // Access the default export (the factory function) and invoke it const uu = urlUnshortModule.default(); // Same usage as above uu.expand('https://bit.ly/example') .then(longUrl => console.log('Expanded URL:', longUrl)) .catch(err => console.error('Error expanding URL:', err));
Important Note for Node.js
Make sure your project is configured to use ES6 modules:
- Add
"type": "module"to yourpackage.jsonfile. - If you're using a file extension, use
.mjsinstead of.js(though thepackage.jsonsetting makes.jswork for ES6 modules).
内容的提问来源于stack exchange,提问作者Cif

