多独立JSON对象数据下，如何遍历获取指定batman对象数据？

Hey there! Let's break down why your previous attempts didn't work and how to grab that batman object correctly.

First off, a key point: you're working with three separate JSON objects, not a single large object containing all three keys, nor an array of objects. That's exactly why data['batman'] and data[0][batman] didn't give you what you needed.

解决思路 #

We need to first organize these standalone JSON strings into a traversable structure, then parse each one and look for the object that has the batman key.

具体实现代码 #

Assuming your raw data exists as a collection of strings, here's how to handle it:

// First, wrap all your standalone JSON strings into an array
const rawData = [
  '{"joker":{"baseMapId":"1536abe5e5504e5db380ccfaa9b6fd8d","customBaseMap":"","zoomn":"5","orient":"0","centLon":"-93.69999999999843","centLat":"38.64999999999935","baseMapLabels":"true"}}',
  '{"batman":{"baseMapId":"1536abe5e5504e5db380ccfaa9b6fd8d","customBaseMap":"","zoomn":"5","orient":"0","centLon":"-93.69999999999843","centLat":"38.64999999999935","baseMapLabels":"true"}}',
  '{"merman":{"baseMapId":"1536abe5e5504e5db380ccfaa9b6fd8d","customBaseMap":"","zoomn":"5","orient":"0","centLon":"-93.69999999999843","centLat":"38.64999999999935","baseMapLabels":"true"}}'
];

// Option 1: Use a loop to find the target
let batmanResult = null;
for (const jsonStr of rawData) {
  const parsedObj = JSON.parse(jsonStr);
  if (parsedObj.hasOwnProperty('batman')) {
    batmanResult = parsedObj;
    break; // Stop searching once we find it
  }
}

// Option 2: A more concise approach with array methods
const batmanResult = rawData
  .map(str => JSON.parse(str))
  .find(obj => obj.hasOwnProperty('batman'));

// Log the result you want
console.log(batmanResult);

为什么之前的尝试失败？ #

• data['batman']: This assumes data is a single object that directly contains the batman key. But your data is three separate objects, so this lookup can't find anything.
• data[0][batman]: If data was an array, data[0] would be the object containing joker—which doesn't have a batman key. Also, batman isn't wrapped in quotes, so it's treated as a variable instead of a string key. Even if you wrote data[0]['batman'], it still wouldn't work since the first object has no such key.

内容的提问来源于stack exchange，提问作者Lieutenant Dan