如何在Python中读取多层JSON结构里child节点的component_name？

现有如下多层JSON结构，已编写部分Python代码读取该JSON文件，需要读取其中desktop节点下child数组内的component_name字段，请求实现方法。

JSON文件内容 #

{
   "layout": {
      "user": {
         "pages": {
             "Home": {
                "sub_domain_name": "abcd",
                   "title": "Home",
                    "page_id": 1111111,
                    "is_login_required": false,
                    "description": "Description",
                    "sequence": "1",
                    "desktop": [
                        {
                            "name": "row",
                            "component_id": "31fac419-f1ff-4614",
                            "main_classes": "border-bottom-0 me",
                            "child": [
                                {
                                    "name": "col",
                                    "component_id": "087851bc",
                                    "component_name": "Card",
                                    "size": "12",
                                    "main_classes": "-",
                                    "classes": "display-6",
                                    "height": "-",
                                    "width": "-",
                                    "items": []
                                }
                            ]
                        }
                    ]
                }
            }
        }
    }
}

现有Python代码 #

import json
myJsonFile=open("config-2.json")#open json file
jsondata=myJsonFile.read()#read json file
#parse
obj=json.loads(jsondata)#store json data in object
list=obj['layout']#read first node
print("Length:",len(list))
for i in list:
    inner_page=list[i]['pages']#read pages node
    pages_list=inner_page.keys()
    for j in pages_list:
        desktop=inner_page[j]['desktop']#read desktop node
        print(desktop)#print desktop node
        for k in desktop:
            print("Component Name:",k['name'])

解决方案 #

要读取child数组内的component_name字段，只需在遍历desktop数组的循环中，进一步遍历每个row节点下的child数组，提取对应字段即可。修改后的代码如下：

import json
# 用with语句打开文件，自动处理文件关闭
with open("config-2.json") as myJsonFile:
    jsondata = myJsonFile.read()

# 解析JSON数据
obj = json.loads(jsondata)
layout = obj['layout']

for key in layout:
    inner_page = layout[key]['pages']
    pages_list = inner_page.keys()
    for page_name in pages_list:
        desktop = inner_page[page_name]['desktop']
        # 遍历desktop中的每个row节点
        for row in desktop:
            # 遍历row下的child数组，提取component_name
            for child_item in row['child']:
                print("Component Name:", child_item['component_name'])

补充说明 #

• 如果child数组可能为空，可以添加判断避免报错：

  for row in desktop:
      # 先判断child数组是否存在且非空
      if row.get('child'):
          for child_item in row['child']:
              print("Component Name:", child_item['component_name'])
  

内容的提问来源于stack exchange，提问作者Pooja Patil