Pine Script代码优化：解决request.security调用超限问题

运行Pine Script代码时触发错误：Script requests too many securities: 50. The limit is 40。
代码通过多次调用request.security，获取s01至s06共6个交易对在5、15、30、60、120、240分钟这6种时间周期下的EMA交叉相关数据，需要简化代码减少request.security调用次数。原代码如下：

screener_func() =>
    ema12 = ta.ema(close,12)
    ema26 = ta.ema(close,26) 
    crossdown = ta.crossunder(expma12, expma26)
    crossup = ta.crossover(expma12, expma26)
    HitungBarEma = ta.barssince(crossdown or crossup)

array.push(EmaPair1, EmaPair1_1)  

[EmaPair1_1] = request.security(s01, '5', screener_func())  
[EmaPair1_2] = request.security(s01, '15', screener_func())  
[EmaPair1_3] = request.security(s01, '30', screener_func())  
[EmaPair1_4] = request.security(s01, '60', screener_func())  
[EmaPair1_5] = request.security(s01, '120', screener_func())  
[EmaPair1_6] = request.security(s01, '240', screener_func())  

[EmaPair2_1] = request.security(s02, '5', screener_func())  
[EmaPair2_2] = request.security(s02, '15', screener_func())  
[EmaPair2_3] = request.security(s02, '30', screener_func())  
[EmaPair2_4] = request.security(s02, '60', screener_func())  
[EmaPair2_5] = request.security(s02, '120', screener_func())  
[EmaPair2_6] = request.security(s02, '240', screener_func())  

[EmaPair3_1] = request.security(s03, '5', screener_func())  
[EmaPair3_2] = request.security(s03, '15', screener_func())  
[EmaPair3_3] = request.security(s03, '30', screener_func())  
[EmaPair3_4] = request.security(s03, '60', screener_func())  
[EmaPair3_5] = request.security(s03, '120', screener_func())  
[EmaPair3_6] = request.security(s03, '240', screener_func())  

[EmaPair4_1] = request.security(s04, '5', screener_func())  
[EmaPair4_2] = request.security(s04, '15', screener_func())  
[EmaPair4_3] = request.security(s04, '30', screener_func())  
[EmaPair4_4] = request.security(s04, '60', screener_func())  
[EmaPair4_5] = request.security(s04, '120', screener_func())  
[EmaPair4_6] = request.security(s04, '240', screener_func())  

[EmaPair5_1] = request.security(s05, '5', screener_func())  
[EmaPair5_2] = request.security(s05, '15', screener_func())  
[EmaPair5_3] = request.security(s05, '30', screener_func())  
[EmaPair5_4] = request.security(s05, '60', screener_func())  
[EmaPair5_5] = request.security(s05, '120', screener_func())  
[EmaPair5_6] = request.security(s05, '240', screener_func())  

[EmaPair6_1] = request.security(s06, '5', screener_func())  
[EmaPair6_2] = request.security(s06, '15', screener_func())  
[EmaPair6_3] = request.security(s06, '30', screener_func())  
[EmaPair6_4] = request.security(s06, '60', screener_func())  
[EmaPair6_5] = request.security(s06, '120', screener_func())  
[EmaPair6_6] = request.security(s06, '240', screener_func())  

使用request.security_all一次性获取多个标的在同一周期的数据，将request.security类调用的总次数从36次降至6次（对应6个时间周期），完全符合40次的限制要求。

1. 定义标的和时间周期数组 #

// 存储需要查询的6个交易对
symbols = [s01, s02, s03, s04, s05, s06]
// 存储需要查询的6个时间周期
timeframes = ['5', '15', '30', '60', '120', '240']

2. 编写单周期EMA交叉数据计算函数 #

修正原代码的变量名错误（expma12/expma26应为ema12/ema26），编写通用计算函数：

calc_ema_cross_data() =>
    ema12 = ta.ema(close, 12)
    ema26 = ta.ema(close, 26)
    crossdown = ta.crossunder(ema12, ema26)
    crossup = ta.crossover(ema12, ema26)
    ta.barssince(crossdown or crossup)

3. 批量获取所有周期的标的数据 #

遍历每个时间周期，用request.security_all一次性获取当前周期下所有标的的数据：

// 存储最终结果：外层数组对应时间周期，内层数组对应标的数据
var all_results = array.new_array()

for tf in timeframes
    // 单次调用获取当前周期下6个标的的EMA交叉数据
    period_data = request.security_all(symbols, tf, calc_ema_cross_data())
    array.push(all_results, period_data)

4. 访问目标数据 #

通过数组索引匹配原代码的变量逻辑：

// 示例：获取s01在5分钟周期的数据（s01是symbols第0位，5分钟是timeframes第0位）
EmaPair1_1 = array.get(array.get(all_results, 0), 0)

// 获取s02在15分钟周期的数据（s02是symbols第1位，15分钟是timeframes第1位）
EmaPair2_2 = array.get(array.get(all_results, 1), 1)

// 原代码变量对应关系：
// EmaPairX_Y → symbols[X-1]，timeframes[Y-1]
// 比如EmaPair3_4（s03的60分钟数据）→ array.get(array.get(all_results, 3), 2)

内容的提问来源于stack exchange，提问作者EMPTY