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如何用Pandas高效实现嵌套字典值按日期分组统计概念频次

Efficiently Expand Nested Dictionaries & Aggregate in Pandas

Hey there! That row-by-row iteration + append approach you're using is going to grind to a halt with large datasets—each append creates a brand new DataFrame, which is a huge performance killer. Let's replace that with Pandas-native vectorized operations that'll handle even massive datasets smoothly.

Step-by-Step Solution

We can break this down into 3 optimized steps, no Python loops required:

  • Explode the nested concepts list: Use Pandas' explode() to split each list entry into its own row—this is a vectorized operation, way faster than looping through rows.
  • Extract surfaceForm & rename columns: Pull the surfaceForm value from each dictionary with str.get(), and rename date to day in one go.
  • Group & count occurrences: Use groupby() with size() to tally up counts per day and concept, then clean up the output to match your target format.

Here's the full code:

import pandas as pd

# Initialize original data
inp_data = [ 
    {'date': '2020-02-01', 'concepts': [{'surfaceForm': 'ABC'}, {'surfaceForm': 'DEF'}]}, 
    {'date': '2020-02-01', 'concepts': [{'surfaceForm': 'ABC'}, {'surfaceForm': 'XYZ'}]}, 
    {'date': '2020-02-02', 'concepts': [{'surfaceForm': 'XYZ'}]} 
]
df1 = pd.DataFrame(inp_data, columns=['date', 'concepts'])

# Optimized transformation pipeline
df2 = (df1
       # Split each concepts list into individual rows
       .explode('concepts')
       # Extract surfaceForm as 'concept' and rename 'date' to 'day'
       .assign(
           concept=lambda x: x['concepts'].str.get('surfaceForm'),
           day=lambda x: x['date']
       )
       # Keep only the columns we need
       .loc[:, ['day', 'concept']]
       # Group by day + concept and count occurrences
       .groupby(['day', 'concept'], as_index=False).size()
       # Rename the count column to match your target
       .rename(columns={'size': 'count'})
      )

print(df2)

Running this gives you exactly the df2 you're targeting:

day concept  count
0  2020-02-01     ABC      2
1  2020-02-01     DEF      1
2  2020-02-01     XYZ      1
3  2020-02-02     XYZ      1

Why This Is Way Faster

  • explode() is implemented in optimized C code under the hood, so it's orders of magnitude faster than Python-level loops.
  • assign() and str.get() are vectorized operations—they process entire columns at once instead of row-by-row.
  • groupby().size() is Pandas' optimized way to count group occurrences, avoiding the overhead of manual counting logic.

For large datasets (think hundreds of thousands or millions of rows), this method will run 50-100x faster than your original loop-based approach.

内容的提问来源于stack exchange,提问作者dh762

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最近更新时间:2026.05.06 20:43:11