如何用Python循环并递增生成带编号的XML问答节点

现有Python代码 #

linenum = 1
for g in u.answers:
    attr = ""
    lines.append("\t\t<answer%s>%s</answer>" % (attr, g[0]))
    linenum += 1

当前生成的XML内容 #

<xml>
    <answer>Primary Job Function</answer>
    <answer>Engineering</answer>
    <answer>Size of Company</answer>
    <answer>100</answer>
    <answer>Job Level</answer>
    <answer>Manager</answer>
    <answer>Type of Company</answer>
    <answer>Supplier</answer>
<xml>

期望生成的XML内容 #

<xml>
    <question1>Primary Job Function</question1>
    <answer1>Engineering</answer1>
    <question2>Size of Company</question2>
    <answer2>100</answer2>
    <question3>Job Level</question3>
    <answer3>Manager</answer3>
    <question4>Type of Company</question4>
    <answer4>Supplier</answer4>
</xml>

修改后的代码 #

linenum = 1
# 每两个元素为一组遍历（对应问题+回答）
for i in range(0, len(u.answers), 2):
    lines.append(f"\t\t<question{linenum}>{u.answers[i][0]}</question{linenum}>")
    lines.append(f"\t\t<answer{linenum}>{u.answers[i+1][0]}</answer{linenum}>")
    linenum += 1

代码说明 #

• 用range(0, len(u.answers), 2)实现按问题+回答的组来遍历，刚好匹配你要的成对节点结构
• 改用f-string格式化字符串，比原来的%格式化更直观，方便插入编号
• 每组遍历后递增linenum，保证question和answer的编号一一对应且连续递增

内容的提问来源于stack exchange，提问作者user1787060