如何将提取的车站与位置列表转换为指定格式字符串并换行打印

原文本数据 #

text_file = "London Euston 12 London 56, Aylesbury Vale 87 Parkway 99, James Cook 76 University 87, Virginia Water 42 Surrey 78"

期望输出 #

Stations:
London Euston
Aylesbury Vale
James Cook
Virginia Water

Locations:
12 London 56
87 Parkway 99
76 University 87
42 Surrey 78

当前代码（存在两处问题） #

replaced = text_file.replace(","," ")
replaced_split = replaced.split()

i = 0
b = 2
stations = []
locations = []

while b < len(replaced_split):
   locations.append(replaced_split[b:b+3])
   b += 5

while i < len(replaced_split):
   stations.append(replaced_split[i:i+2])
   i += 5

for x in range(len(stations)):
   print(stations[x])

for y in range(len(locations)):
   print(dates[y])

当前错误输出 #

['London', 'Euston']
['Aylesbury', 'Vale']
['James', 'Cook']
['Virginia', 'Water']
['12', 'London', '56']
['87', 'Parkway', '99']
['76', 'University', '87']
['42', 'Surrey', '78']

修正方案 #

直接修改现有代码，解决核心问题：

1. 用' '.join()方法将子列表元素拼接成字符串，避免输出列表对象格式
2. 修正变量名错误，把dates[y]改为locations[y]
3. 添加要求的标题和分隔空行，匹配期望输出格式

修正后的代码：

text_file = "London Euston 12 London 56, Aylesbury Vale 87 Parkway 99, James Cook 76 University 87, Virginia Water 42 Surrey 78"

replaced = text_file.replace(","," ")
replaced_split = replaced.split()

i = 0
b = 2
stations = []
locations = []

while b < len(replaced_split):
   # 直接拼接成字符串存入列表
   locations.append(' '.join(replaced_split[b:b+3]))
   b += 5

while i < len(replaced_split):
   # 直接拼接成字符串存入列表
   stations.append(' '.join(replaced_split[i:i+2]))
   i += 5

# 按要求格式输出
print("Stations:")
for station in stations:
   print(station)

# 空行分隔
print()

print("Locations:")
for location in locations:
   print(location)

运行这段代码即可得到符合要求的输出结果。

内容的提问来源于stack exchange，提问作者Still Learning