Python猜谜游戏问题：猜对后仍触发提示语句的解决求助

核心问题：提示输出逻辑未与「猜错」操作绑定，无论猜对猜错都会执行提示代码，导致猜对时仍显示不必要的提示。

修改后的代码 #

secret_w = "giraffe"
guess= ""
guess_remain = 3
guess_c = 0
guess_limit = 2
outofguesses = False

while guess != secret_w and not(outofguesses):
    guess = input("I'm thinking of an animal, try and guess it!  ")
    guess_c += 1
    if guess != secret_w:
        print("Incorrect, try again")
        guess_remain -= 1
        print("You've guessed", guess_c, "times and have", guess_remain, "guesses left!")
        
        # 仅在猜错时触发提示
        if guess_c == 1:
            print("Hint 1: It's tall!")
        if guess_c == 2:
            print("Hint 2: It has spots and a long neck")

    if guess_c > guess_limit:
        outofguesses = True

if outofguesses:
    print("You're out of guesses, better luck next time!")

if guess == secret_w:
    print("Well done")
    print("You got it on attempt number", guess_c )

修改说明 #

将两个提示输出的if判断语句，移动到if guess != secret_w:的代码块内部。这样只有当用户猜错时，才会根据当前的猜测次数显示对应提示；如果猜对，会直接跳过这段提示逻辑，符合预期效果。

内容的提问来源于stack exchange，提问作者matthewwaring