咨询仅可将元素移至列表尾部的算法名称及应用可行性

Hey there! Great question—yes, such an algorithm does exist, and it's a variant of selection sort tailored to the "move element to list tail" operation constraint. It's commonly referred to as Move-to-End Selection Sort (or sometimes just Tail-Move Sort for short).

How it works with your example: #

Let's walk through transforming initial_list = [4, 2, 3, 1] into desired_list = [1, 2, 3, 4] step by step:

• First, identify the smallest element in the entire list: 1. It's positioned at index 3. To get it to the front, we move every element before it to the tail one by one:
  • Move 4 to tail → [2, 3, 1, 4]
  • Move 2 to tail → [3, 1, 4, 2]
  • Move 3 to tail → [1, 4, 2, 3]
• Now the first element is correct. Focus on the remaining unsorted sublist [4, 2, 3]:
  • Find the smallest element here: 2, which is at index 2 of the full list. Move the element before it (4) to the tail → [1, 2, 3, 4]
• The list is now fully sorted!

Key Details: #

• The core idea mirrors selection sort: repeatedly find the minimum element in the unsorted portion of the list, then shift all elements before it to the tail (effectively bringing the minimum element to the start of the unsorted section).
• Time complexity is O(n²) in the worst case, since for each of the n elements, you might need to move up to n-1 elements to the tail.
• It's a simple, intuitive algorithm for scenarios where moving elements to the end is the only allowed modification (like certain queue-based data structures).

内容的提问来源于stack exchange，提问作者pluff