如何在Robot Framework中用循环改写重复的下拉选择测试代码？

问题背景 #

正在学习Robot Framework，为提升代码可维护性，尝试用循环替代重复代码。现有一组带下拉选项的测试题，需每次运行测试时随机选择不同答案，但尝试的FOR循环因变量拼接问题无法正常工作。

原重复代码 #

Check if User can change "Company" information
    Scroll Element Into View                ${USER_MENU_SCROLL_TO_COMPANY_MENU}
    sleep                                   1s
    click element                           ${USER_MENU_CLICK_COMPANY_EDIT_BUTTON}
    ${random_description1} =                 Evaluate  random.choice(@{USER_MENU_DROP_DOWN_QUESTION1})
    click element                           ${random_description1}
    sleep                                   1s
    click element                           ${USER_MENU_CLICK_DROP_DOWN_2}
    ${random_description2} =                 Evaluate  random.choice(@{USER_MENU_DROP_DOWN_QUESTION2})
    click element                           ${random_description2}
    sleep                                   1s
    click element                           ${USER_MENU_CLICK_DROP_DOWN_3}
    ${random_description3} =                 Evaluate  random.choice(@{USER_MENU_DROP_DOWN_QUESTION3})
    click element                           ${random_description3}
    sleep                                   1s
    click element                           ${USER_MENU_CLICK_DROP_DOWN_4}
    ${random_description4} =                 Evaluate  random.choice(@{USER_MENU_DROP_DOWN_QUESTION4})
    click element                           ${random_description4}
    sleep                                   1s
    click element                           ${USER_MENU_CLICK_DROP_DOWN_5}
    ${random_description5} =                 Evaluate  random.choice(@{USER_MENU_DROP_DOWN_QUESTION5})
    click element                           ${random_description5}

尝试的错误循环代码 #

FOR ${i} IN RANGE 1 5
    ${random_description} = Evaluate random.choice(@{USER_MENU_DROP_DOWN_QUESTION}+${i})
    click element ${USER_MENU_CLICK_DROP_DOWN_}+${i}
    click element ${random_description}
    sleep 1s
END

正确实现方案 #

方案1：使用Get Variable Value动态解析变量 #

Robot Framework不支持直接拼接变量名的方式获取变量，需要用Get Variable Value关键字动态解析带序号的变量：

Check if User can change "Company" information
    Scroll Element Into View                ${USER_MENU_SCROLL_TO_COMPANY_MENU}
    sleep                                   1s
    click element                           ${USER_MENU_CLICK_COMPANY_EDIT_BUTTON}
    # RANGE 1 6 会生成1-5的序号（左闭右开）
    FOR    ${i}    IN RANGE    1    6
        # 动态获取对应序号的下拉按钮元素
        ${drop_down_btn} =    Get Variable Value    ${USER_MENU_CLICK_DROP_DOWN_${i}}
        click element    ${drop_down_btn}
        # 动态获取对应序号的下拉选项列表并随机选择
        ${options_list} =    Get Variable Value    ${USER_MENU_DROP_DOWN_QUESTION${i}}
        ${random_option} =    Evaluate    random.choice(${options_list})
        click element    ${random_option}
        sleep    1s
    END

方案2：使用列表批量存储元素（更易维护） #

提前将下拉按钮和选项列表存入列表变量，通过IN ZIP同时遍历两个列表，代码更直观：

步骤1：定义列表变量

*** Variables ***
@{DROP_DOWN_BUTTONS}    ${USER_MENU_CLICK_DROP_DOWN_1}    ${USER_MENU_CLICK_DROP_DOWN_2}    ${USER_MENU_CLICK_DROP_DOWN_3}    ${USER_MENU_CLICK_DROP_DOWN_4}    ${USER_MENU_CLICK_DROP_DOWN_5}
@{DROP_DOWN_OPTIONS}    ${USER_MENU_DROP_DOWN_QUESTION1}    ${USER_MENU_DROP_DOWN_QUESTION2}    ${USER_MENU_DROP_DOWN_QUESTION3}    ${USER_MENU_DROP_DOWN_QUESTION4}    ${USER_MENU_DROP_DOWN_QUESTION5}

步骤2：编写循环测试用例

Check if User can change "Company" information
    Scroll Element Into View                ${USER_MENU_SCROLL_TO_COMPANY_MENU}
    sleep                                   1s
    click element                           ${USER_MENU_CLICK_COMPANY_EDIT_BUTTON}
    # 同时遍历按钮列表和选项列表
    FOR    ${btn}    ${opts}    IN ZIP    ${DROP_DOWN_BUTTONS}    ${DROP_DOWN_OPTIONS}
        click element    ${btn}
        ${random_option} =    Evaluate    random.choice(${opts})
        click element    ${random_option}
        sleep    1s
    END

这种方式后续新增下拉项时，只需在列表变量中添加对应元素即可，无需修改循环逻辑，可维护性更高。

内容的提问来源于stack exchange，提问作者AM0801