如何实现2分钟EMA交叉后结合10分钟RSI均线交叉输出对应信号？

我编写的Pine Script在2分钟K线图上，当9周期EMA与50周期EMA交叉时会交替生成多/空信号，该功能运行正常。现在需要实现：

• 仅当10分钟K线图上的RSI向上交叉其均线时，才输出2分钟图的多单信号
• 仅当10分钟K线图上的RSI向下交叉其均线时，才输出2分钟图的空单信号

我尝试多种方法均未成功，已定义rsi_trigger变量，但不知如何将其整合到longsignal/shortsignal的判断逻辑中，原代码如下：

//EMAs
ema9 = ta.ema(close, input.int(9, 'EMA9'))
ema50 = ta.ema(close, input.int(50, 'EMA50'))

//RSI
rsi15 = ta.rsi(close, 15)

//RSI Moving Average
rsi20_moving_avg = ta.rma(close, 20)

ten_min_rsi_15 = request.security(syminfo.tickerid, '10', rsi15)
ten_min_rsi_ma_20 = request.security(syminfo.tickerid, '10', rsi20_moving_avg)

// we create a variable that "saves" and doesnt calc on each bar 
var cross_trigger = 0
var rsi_trigger = 0

// we save it to a new number when long happens. Long can be 1 
if ta.crossover(ema9, ema50) and cross_trigger <= 0
    cross_trigger := 1
// we save it again when short happens. Short can be -1 
if ta.crossover(ema50, ema9) and cross_trigger >= 0 
    cross_trigger := -1

if (ten_min_rsi_15 > ten_min_rsi_ma_20) and rsi_trigger <= 0
    rsi_trigger := 1

if (ten_min_rsi_15 < ten_min_rsi_ma_20) and rsi_trigger >= 0
    rsi_trigger := -1

// here we check if we have a newly detetected change from another number to our pos number this bar
// Is pos equal to 1 and was it not equal to 1 one bar ago
longsignal  = cross_trigger ==  1 and (cross_trigger !=  1)[1]
shortsignal = cross_trigger == -1 and (cross_trigger != -1)[1]

//Plot
// we change our plot shape to coincide with the change detection 
plotshape(longsignal,  style=shape.triangleup, color=#26a69a, text="LONG", textcolor=#ffffff, location=location.bottom, size=size.small)
plotshape(shortsignal, style=shape.triangledown, color=#ef5350, text="SHORT", textcolor=#ffffff, location=location.top, size=size.small)

// Alerts
alertcondition(longsignal, title='CALL', message='CALL')
alertcondition(shortsignal, title='PUT', message='PUT')

核心问题是当前的rsi_trigger仅记录了10分钟RSI与均线的位置关系，未捕捉交叉动作，且未将EMA交叉信号与对应的RSI交叉条件绑定。以下是修改后的代码：

//EMAs
ema9 = ta.ema(close, input.int(9, 'EMA9'))
ema50 = ta.ema(close, input.int(50, 'EMA50'))

//RSI与均线计算
rsi15 = ta.rsi(close, 15)
rsi20_moving_avg = ta.rma(rsi15, 20)  // 修正：原代码用close计算RSI均线，应改用RSI值本身

// 获取10分钟周期的RSI交叉信号
ten_min_rsi_cross_up = request.security(syminfo.tickerid, '10', ta.crossover(rsi15, rsi20_moving_avg))
ten_min_rsi_cross_down = request.security(syminfo.tickerid, '10', ta.crossunder(rsi15, rsi20_moving_avg))

// 记录EMA交叉的触发状态，仅在对应RSI交叉条件满足时更新
var cross_trigger = 0

// 多单触发：EMA9上穿EMA50 + 10分钟RSI上穿均线
if ta.crossover(ema9, ema50) and cross_trigger <= 0 and ten_min_rsi_cross_up
    cross_trigger := 1

// 空单触发：EMA50上穿EMA9 + 10分钟RSI下穿均线
if ta.crossover(ema50, ema9) and cross_trigger >= 0 and ten_min_rsi_cross_down
    cross_trigger := -1

// 检测状态变化，生成最终信号
longsignal  = cross_trigger == 1 and cross_trigger[1] != 1
shortsignal = cross_trigger == -1 and cross_trigger[1] != -1

// 绘图
plotshape(longsignal,  style=shape.triangleup, color=#26a69a, text="LONG", textcolor=#ffffff, location=location.bottom, size=size.small)
plotshape(shortsignal, style=shape.triangledown, color=#ef5350, text="SHORT", textcolor=#ffffff, location=location.top, size=size.small)

// 警报
alertcondition(longsignal, title='CALL', message='CALL')
alertcondition(shortsignal, title='PUT', message='PUT')

1. 修正RSI均线计算：原代码误用close计算RSI的均线，改为用RSI指标本身的值rsi15计算，逻辑更合理
2. 捕捉10分钟RSI交叉事件：直接在跨周期请求中调用ta.crossover和ta.crossunder，精准获取10分钟周期上的RSI交叉信号
3. 绑定EMA与RSI交叉条件：更新cross_trigger时，必须同时满足EMA交叉和对应的10分钟RSI交叉条件，确保两个周期信号共振才触发
4. 保留原有信号去重逻辑：继续通过cross_trigger的状态变化检测最终信号，避免连续输出重复信号

内容的提问来源于stack exchange，提问作者user12351824