Python版Rock Paper Scissors Lizard Spock游戏：多次运行结果重复问题求助

核心问题1：随机动作重复 #

你把user_action和computer_action的生成放在了循环外面，这两个变量只会被赋值一次，循环里反复用同一个动作，自然每次结果都一样。

核心问题2：结果列表存的都是None #

determine_winner函数只有print输出，没有返回任何值，所以你append到res里的都是函数默认返回的None。

修正后的代码 #

from enum import IntEnum
import random

class Action(IntEnum):
    Rock = 0
    Paper = 1
    Scissors = 2
    Lizard = 3
    Spock = 4

victories = {
    Action.Scissors: [Action.Lizard, Action.Paper],
    Action.Paper: [Action.Spock, Action.Rock],
    Action.Rock: [Action.Lizard, Action.Scissors],
    Action.Lizard: [Action.Spock, Action.Paper],
    Action.Spock: [Action.Scissors, Action.Rock]
}

def get_user_selection():
    selection = random.randint(0, len(Action) - 1)
    return Action(selection)

def get_computer_selection():
    selection = random.randint(0, len(Action) - 1)
    return Action(selection)

def determine_winner(user_action, computer_action):
    defeats = victories[user_action]
    if user_action == computer_action:
        result = f"Both players selected {user_action.name}. It's a tie!"
    elif computer_action in defeats:
        result = f"{user_action.name} beats {computer_action.name}! You win!"
    else:
        result = f"{computer_action.name} beats {user_action.name}! You lose."
    print(result)
    return result  # 返回结果，方便存入列表

res = []
for n in range(5):
    # 每次循环都重新生成随机动作
    user_action = get_user_selection()
    computer_action = get_computer_selection()
    new_result = determine_winner(user_action, computer_action)
    res.append(new_result)
    print(res)

关键修改点 #

• 把user_action和computer_action的生成移到for循环内部，每次循环都会重新生成随机动作。
• 给determine_winner函数添加return语句，返回生成的结果字符串，这样res列表里就能存实际的结果内容。
• 补充了缺失的from enum import IntEnum和import random导入语句（原代码里没写，运行会报错）。

内容的提问来源于stack exchange，提问作者Asma Ahmed