PostgreSQL中如何筛选仅购买travel产品的用户并统计订单数
PostgreSQL筛选仅购买travel产品的用户并统计订单数
需要从购买过travel或books产品的用户列表中,筛选出仅购买过travel产品的用户,并统计这些用户的订单数量。期望结果如下:
user_id count_orders ----------------------- 4 5 6 2
表结构与测试数据
CREATE TABLE orders ( user_id INTEGER, order_id INTEGER, order_date DATE, price FLOAT, product VARCHAR(255) ); INSERT INTO orders(user_id, order_id, order_date, price, product) VALUES (1, 2, '2021-03-05', 15, 'books'), (1, 13, '2022-03-07', 3, 'music'), (1, 14, '2022-06-15', 900, 'travel'), (1, 11, '2021-11-17', 25, 'books'), (1, 16, '2022-08-03', 32, 'books'), (2, 4, '2021-04-12', 4, 'music'), (2, 7, '2021-06-29', 9, 'music'), (2, 20, '2022-11-03', 8, 'music'), (2, 22, '2022-11-07', 575, 'travel'), (2, 24, '2022-11-20', 95, 'food'), (3, 3, '2021-03-17', 25, 'books'), (3, 5, '2021-06-01', 650, 'travel'), (3, 17, '2022-08-17', 1200, 'travel'), (3, 19, '2022-10-02', 6, 'music'), (3, 23, '2022-11-08', 7, 'food'), (4, 9, '2021-08-20', 3200, 'travel'), (4, 10, '2021-10-29', 2750, 'travel'), (4, 15, '2022-07-15', 1820, 'travel'), (4, 21, '2022-11-05', 8000, 'travel'), (4, 25, '2022-11-29', 2300, 'travel'), (5, 1, '2021-01-04', 3, 'music'), (5, 6, '2021-06-09', 820, 'travel'), (5, 8, '2021-07-30', 19, 'books'), (5, 12, '2021-12-10', 22, 'music'), (5, 18, '2022-09-19', 20, 'books'), (6, 26, '2023-01-09', 700, 'travel'), (6, 27, '2023-01-23', 1900, 'travel');
解决方案SQL
写法一:分组过滤法
SELECT user_id, COUNT(order_id) AS count_orders FROM orders WHERE user_id IN ( SELECT user_id FROM orders WHERE product IN ('travel', 'books') ) GROUP BY user_id HAVING COUNT(DISTINCT product) = 1 AND MAX(product) = 'travel';
写法二:排除过滤法
SELECT user_id, COUNT(order_id) AS count_orders FROM orders WHERE user_id NOT IN ( SELECT user_id FROM orders WHERE product = 'books' ) AND user_id IN ( SELECT user_id FROM orders WHERE product = 'travel' ) GROUP BY user_id;
思路说明
- 写法一:先通过子查询锁定购买过
travel或books的用户范围,再对用户分组,用HAVING子句确保用户仅购买过travel这一种产品,最后统计订单数。 - 写法二:逻辑更直观,先排除所有购买过
books的用户,再筛选出购买过travel的用户,最后统计这些用户的订单总数。
内容的提问来源于stack exchange,提问作者zeroes_ones
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