Tkinter选项菜单选择后调用对应函数的实现问题求助

import pandas as pd
import matplotlib.pyplot as plt 
import tkinter as tk
from tkinter import filedialog, StringVar, OptionMenu

# 读取数据
root = tk.Tk()
root.withdraw()

file_path = filedialog.askopenfilename()
df = pd.read_csv(file_path) 
df.rename(columns={'Unnamed: 0':'Type'}, inplace=True)
df.dropna(how='all', axis=1, inplace=True)

## 绘图函数
def ActivePokes(): 
    plt.rcParams["figure.figsize"] = (12,7.5)
    df.plot()
    plt.xticks(range(0, len(df.Type)), df.Type)
    plt.ylabel("Number of Active Pokes")
    plt.xlabel("Sessions")
    plt.title("Number of Active Pokes vs Drug Availability")
    plt.show()
    
def InactivePokes(): 
    plt.rcParams["figure.figsize"] = (12,7.5)
    df.plot()
    plt.xticks(range(0, len(df.Type)), df.Type)
    plt.ylabel("Number of Inactive Pokes")
    plt.xlabel("Sessions")
    plt.title("Number of Inactive Pokes vs Drug Availability")
    plt.show()
    
def show(selected_option): 
    if selected_option == options[1]:
        ActivePokes()
    elif selected_option == options[2]: 
        InactivePokes()
    # 默认选项不执行操作

options = [
    "Choose Option",
    "1. Active pokes, Drug Available and No Drug Available sessions", 
    "2. Inactive pokes, Drug Available and No Drug Available sessions"
]

# 创建主窗口
main_window = tk.Tk()
main_window.title("Dialog Window")
main_window.geometry('500x90')

variable = StringVar(main_window)
variable.set(options[0])

option_menu = OptionMenu(main_window, variable, *options, command=show)
option_menu.pack()

main_window.mainloop()

• 清理冗余导入：删除重复导入的模块，保持代码简洁
• 调整show函数参数：OptionMenu的command回调会自动传入当前选中的选项文本，show函数通过该参数判断用户选择
• 直接调用目标函数：去掉错误的button[command]赋值逻辑，在show中直接调用对应绘图函数，避免函数提前执行
• 简化绘图函数：利用全局变量df，绘图函数无需额外传参，简化调用逻辑
• 优化窗口命名：将原button变量改为main_window，避免和控件名称混淆，语义更清晰

内容的提问来源于stack exchange，提问作者Hibah Mirza Chughtai