TypeScript问题：无法通过Object.keys()访问子类属性

我希望将基类构造函数中定义的逻辑复用至所有子类，具体来说，想在构造函数中遍历类的所有属性。原本预期在基类构造函数中调用Object.keys()，同时子类构造函数调用super()就能实现该功能，但实际结果不符合预期。

代码示例 #

class BaseClass {
    private baseField1: string;
    private baseField2: string;

    constructor(data: any) {
        console.log(this.constructor.name + " has fields: " + Object.keys(this));
    }
}

class ChildClass extends BaseClass {
    private childField1: string;

    constructor(data: any) {
        super(data);
    }
}

let base = new ChildClass({name: 'Joe'});

预期输出 #

ChildClass has fields: baseField1,baseField2,childField1

实际输出 #

ChildClass has fields: baseField1,baseField2

输出中并未包含childField1属性，请问该如何解决这个问题？

解决方法（更新） #

最终实现了预期效果，感谢Touffy！

class BaseClass {
    private baseField1: string;
    private baseField2: string;

    constructor(data: any) {
        Object.assign(this, data);
    }
}

class ChildClass extends BaseClass {
    private childField1: string;

    constructor(data: any) {
        super(data);
        if (data.childField1) this.childField1 = data.childField1;
    }
}

let base = new ChildClass({
    baseField1: 'bf1',
    baseFileds2: 'bf2', 
    childField1: 'Joe'
});

console.log('Class fields: ' + JSON.stringify(base));

输出结果 #

Class fields: {"baseField1":"bf1","baseFileds2":"bf2","childField1":"Joe"}

内容的提问来源于stack exchange，提问作者Sergei