如何精简JSDARES挑战中JavaScript函数的重复代码？

可以把重复的console.log语句提取到条件判断之外，只针对died字段的特殊情况单独处理，大幅减少代码冗余：

function person(name, born, died, knownFor) {
  console.log("Name      : " + name);
  console.log("Born in   : " + born);
  if (died !== 0) {
    console.log("Died in   : " + died);
  }
  console.log("Known for : " + knownFor);
  console.log("");
}

console.log("Famous people in computing:");
console.log("");
person("Charles Babbage", 1815, 1871, "first computer");
person("Ada Lovelace", 1815, 1852, "first programmer");
person("George Boole", 1815, 1864, "Boolean logic");
person("Grace Hopper", 1906, 1992, "first language");
person("Alan Turing", 1912, 1954, "Turing machine");
person("Douglas Engelbart", 1925, 0, "Computer mouse");
person("Bill Gates", 1955, 0, "Microsoft");
person("Steve Jobs", 1955, 2011, "Apple");
person("Linus Torvalds", 1969, 0, "Linux");
person("Tim Berners-Lee", 1955, 0, "World Wide Web");
console.log("And many more...");

核心思路 #

• 把所有固定输出的内容（姓名、出生年份、成就）放在函数外层，避免在两个分支里重复编写相同代码
• 仅对died字段做条件判断：当died不等于0时，才输出死亡年份行
• 既保留原有逻辑，又将函数内代码从12行精简到7行，同时提升了代码的可读性和维护性

内容的提问来源于stack exchange，提问作者NickyCodeNow