如何用Awk对比两个文件并输出指定格式的匹配内容？

现有两个输入文件，需提取两者共有的:name条目，同时输出file1中该条目下的./name/of/file行，且保留file2中对应:name的完整行。已尝试一段Awk代码，但输出不符合预期，相关信息如下：

已尝试代码 #

awk 'FNR==NR { a[$1]; next }NF<=1{ flag=0 }$1 in a { print; flag=1; delete a[$1]; next }flag{ printf "%s\n",$0 }' file1 file2

当前输出 #

:name1
    ./name/of/file [logfile] [ error in file coming since Day : 1 ]
    ./name/of/file [logfile] [ error in file coming since Day : 1 ]
:name3
    ./name/of/file [logfile] [ error in file coming since Day : 24 ]
    ./name/of/file [logfile] [ error in file coming since Day : 24 ]
:name4
    ./name/of/file [logfile] [ error in file coming since Day : 3 ]
    ./name/of/file [logfile] [ error in file coming since Day : 3 ]
    ./name/of/file [logfile] [ error in file coming since Day : 3 ]
    ./name/of/file [logfile] [ error in file coming since Day : 3 ]

输入文件file1 #

:name1
./name/of/file [logfile] [ error in file coming since Day : 1 ]
./name/of/file [logfile] [ error in file coming since Day : 1 ]

:name2
./name/of/file [logfile] [ error in file coming since Day : 1 ]

:name3
./name/of/file [logfile] [ error in file coming since Day : 24 ]
./name/of/file [logfile] [ error in file coming since Day : 24 ]

 :name1
./name/of/file [logfile] [ error in file coming since Day : 40]
./name/of/file [logfile] [ error in file coming since Day : 40 ]

:name4
./name/of/file [logfile] [ error in file coming since Day : 3 ]
./name/of/file [logfile] [ error in file coming since Day : 3 ]
./name/of/file [logfile] [ error in file coming since Day : 3 ]
./name/of/file [logfile] [ error in file coming since Day : 3 ]

:name5
./name/of/file [logfile] [ error in file coming since Day : 6 ]
./name/of/file [logfile] [ error in file coming since Day : 6 ]

:name4
./name/of/file [logfile] [ error in file coming since Day : 10 ]
./name/of/file [logfile] [ error in file coming since Day : 10 ]
./name/of/file [logfile] [ error in file coming since Day : 10 ]
./name/of/file [logfile] [ error in file coming since Day : 10 ]  

输入文件file2 #

:name1 ABC123 12345
:name3 EFG789 67898
:name4 HIJ547 01234

期望输出 #

:name1 ABC123 12345
    ./name/of/file [logfile] [ error in file coming since Day : 1 ]
    ./name/of/file [logfile] [ error in file coming since Day : 1 ]
:name3 EFG789 67898
    ./name/of/file [logfile] [ error in file coming since Day : 24 ]
    ./name/of/file [logfile] [ error in file coming since Day : 24 ]
:name4 HIJ547 01234
    ./name/of/file [logfile] [ error in file coming since Day : 3 ]
    ./name/of/file [logfile] [ error in file coming since Day : 3 ]
    ./name/of/file [logfile] [ error in file coming since Day : 3 ]
    ./name/of/file [logfile] [ error in file coming since Day : 3 ]

原代码的问题在于处理顺序错误、未处理:name前导空格、未保留file2完整行。修正后的Awk代码如下：

# 读取file2，存储每个:name对应的完整行
FNR == NR {
    name = $1
    name_line[name] = $0
    next
}

# 处理file1中的:name行
/^[[:space:]]*:name/ {
    gsub(/^[[:space:]]*/, "")
    current_name = $0
    collect = (current_name in name_line) ? 1 : 0
    # 仅输出一次file2中的对应行
    if (collect && !printed[current_name]) {
        print name_line[current_name]
        printed[current_name] = 1
    }
    next
}

# 收集并输出file1中的目标文件行（添加缩进）
collect {
    printf "    %s\n", $0
}

执行命令：

awk -f script.awk file2 file1

代码说明 #

1. 先读取file2，用name_line数组保存每个:name对应的完整行
2. 处理file1时，去除:name行的前导空格，判断是否属于file2中的目标条目
3. 首次匹配目标条目时，输出file2中的完整行
4. 后续的./name/of/file行在标记开启时，添加缩进后输出

内容的提问来源于stack exchange，提问作者aastha