如何在Argo Workflow中调用带可选参数的容器命令？

你的原配置问题在于：当long-format为false时，args数组会包含一个空字符串参数，实际执行的是ls "" /etc，这会导致ls尝试列出名为空字符串的文件，不符合预期。下面提供几种可行的解决方案：

方法1：动态生成args数组（推荐） #

利用Argo的模板条件语法直接生成对应参数数组，避免空参数：

apiVersion: argoproj.io/v1alpha1
kind: Workflow
metadata:
  generateName: do-work-
spec:
  arguments:
    parameters:
      - name: long-format
        value: "false"

  entrypoint: do-work

  templates:
    - name: do-work
      container:
        image: alpine:3.7
        command: ["ls"]
        args: >-
          {{- if eq workflow.parameters.long-format "true" }}
          ["-l", "/etc"]
          {{- else }}
          ["/etc"]
          {{- end }}

方法2：条件式添加参数 #

直接在args列表中通过条件判断决定是否添加可选参数，写法更简洁：

apiVersion: argoproj.io/v1alpha1
kind: Workflow
metadata:
  generateName: do-work-
spec:
  arguments:
    parameters:
      - name: long-format
        value: "false"

  entrypoint: do-work

  templates:
    - name: do-work
      container:
        image: alpine:3.7
        command: ["ls"]
        args:
          {{- if eq workflow.parameters.long-format "true" }}
          - "-l"
          {{- end }}
          - "/etc"

方法3：分支模板拆分逻辑 #

如果后续有更多可选参数，将不同场景拆分为独立模板会更清晰：

apiVersion: argoproj.io/v1alpha1
kind: Workflow
metadata:
  generateName: do-work-
spec:
  arguments:
    parameters:
      - name: long-format
        value: "false"

  entrypoint: choose-template

  templates:
    - name: choose-template
      steps:
        - - name: run-command
            template: {{ if eq workflow.parameters.long-format "true" }}ls-long{{ else }}ls-normal{{ end }}

    - name: ls-normal
      container:
        image: alpine:3.7
        command: ["ls", "/etc"]

    - name: ls-long
      container:
        image: alpine:3.7
        command: ["ls", "-l", "/etc"]

验证效果 #

• 执行argo submit do-work.yaml或argo submit do-work.yaml -p long-format=false时，运行ls /etc
• 执行argo submit do-work.yaml -p long-format=true时，运行ls -l /etc

内容的提问来源于stack exchange，提问作者Kevin Pauli