Roblox Studio报错：Entrance不是Model "LongRoomRoof"的有效成员求解决

运行Roblox房间生成代码时触发错误，错误信息如下：

Entrance is not a valid member of Model "LongRoomRoof" - Server - Room:9

涉及代码如下：

ModuleScript 代码 #

local Room = {}
Room.random = Random.new()

function Room.generate(prevRoom)
    local possibleRooms = workspace.Rooms:GetChildren()
    local randomRoom = possibleRooms[Room.random:NextInteger(1, #possibleRooms)]
    local newRoom = randomRoom:Clone()
    
    newRoom.PrimaryPart = newRoom.Entrance
    newRoom:PivotTo(prevRoom.Exit.CFrame)
    newRoom.Entrance.Transparency = 1
    newRoom.Exit.Transparency = 1
    
    newRoom.Parent = workspace.GeneratedRooms
    
    return newRoom
end

return Room

ServerScript 代码 #

local room = require(script.Room)

local prevRoom = workspace.StartRoom

for i = 1, 10 do
    prevRoom = room.generate(prevRoom)
end

• 检查模型完整性：确认workspace.Rooms下所有模型（包括LongRoomRoof）都包含Entrance和Exit部件。若模型缺少这两个部件，要么补全部件，要么将该模型移出Rooms目录。
• 添加有效房间过滤：在ModuleScript中加入逻辑，只筛选包含Entrance和Exit的模型作为候选，避免随机到无效模型。修改后的代码如下：

function Room.generate(prevRoom)
    -- 过滤出包含必要部件的有效房间
    local possibleRooms = {}
    for _, model in ipairs(workspace.Rooms:GetChildren()) do
        if model:FindFirstChild("Entrance") and model:FindFirstChild("Exit") then
            table.insert(possibleRooms, model)
        end
    end

    -- 避免无有效房间时触发索引错误
    if #possibleRooms == 0 then
        warn("没有可用的有效房间模型！")
        return nil
    end
    
    local randomRoom = possibleRooms[Room.random:NextInteger(1, #possibleRooms)]
    local newRoom = randomRoom:Clone()
    
    newRoom.PrimaryPart = newRoom.Entrance
    newRoom:PivotTo(prevRoom.Exit.CFrame)
    newRoom.Entrance.Transparency = 1
    newRoom.Exit.Transparency = 1
    
    newRoom.Parent = workspace.GeneratedRooms
    
    return newRoom
end

• 校验命名规范：确认Entrance和Exit的拼写、大小写完全一致（Roblox部件名称区分大小写），避免因拼写错误导致找不到部件。

内容的提问来源于stack exchange，提问作者Roblox Issue Guy