伪代码中int d[0..m, 0..n]语句的Python解释请求

Hey there! Let's translate that pseudocode line into something you can wrap your head around with Python, since you're still getting started with programming concepts.

First, let's break down what the pseudocode is saying:

• declare int d[0..m, 0..n] creates a 2D table (array) named d designed to hold integers.
• It has m + 1 rows (since row indices run from 0 to m, which includes m+1 total values: 0, 1, ..., m).
• Each row contains n + 1 columns (column indices go from 0 to n, adding up to n+1 values per row).

In Python, we don't "declare" variables with a fixed type like int upfront (Python is dynamically typed), but we can easily build this 2D structure using list comprehensions. Here's how you'd do it, assuming m and n are already defined as integers (like m = 5 or n = 3):

# Create a 2D list with m+1 rows and n+1 columns, all initialized to 0
d = [[0 for _ in range(n + 1)] for _ in range(m + 1)]

Let's unpack this line:

• The outer range(m + 1) generates row indices from 0 to m, giving us m+1 rows total.
• For each row, the inner range(n + 1) generates column indices from 0 to n, so every row has n+1 elements.
• We're initializing every element to 0 here—this is super common for algorithms like edit distance (which your pseudocode snippet looks like it's part of!). If you needed a different starting value, just replace 0 with whatever integer you need.

For example, if m = 2 and n = 3, this code would create a 3-row × 4-column table that looks like this when printed:

[[0, 0, 0, 0],
 [0, 0, 0, 0],
 [0, 0, 0, 0]]

Python doesn't force all elements to be integers, but as long as you only add integer values to this list, it behaves exactly like the int array the pseudocode describes.

内容的提问来源于stack exchange，提问作者Poetry Lion