如何让Python游戏中的while循环动态变更剩余次数提示信息

以下是调整后的代码，实现了根据剩余尝试次数动态提示的功能：

num = 2
guess = None
guess_count = 0
guess_limit = 3
out_of_guesses = False

while guess != num and not out_of_guesses:
    remaining_tries = guess_limit - guess_count
    # 根据剩余次数输出对应提示
    if remaining_tries > 1 and guess_count > 0:
        print(f"WARNING: you have {remaining_tries} amount of tries left")
    elif remaining_tries == 1:
        print("LAST CHANCE")
    
    if guess_count < guess_limit:
        guess = int(input('Guess a number between 1 and 10: '))
        guess_count += 1
    else:
        out_of_guesses = True

if out_of_guesses:
    print('Out of guesses. LOSER!')
else:
    print('BINGO! The third time\'s the CHARM! WINNER!')

关键改动说明 #

• 修正初始guess的类型问题：原代码用空字符串''初始化，会导致第一次循环时字符串与整数的无效比较，改为None更严谨
• 动态计算剩余次数：通过remaining_tries = guess_limit - guess_count实时获取剩余尝试机会
• 分阶段提示：
  • 第一次尝试后（guess_count > 0）且剩余次数大于1时，输出WARNING提示剩余次数
  • 剩余次数只剩1次时，输出LAST CHANCE
• 猜对数字直接终止循环：玩家猜对后会跳出循环，不会触发后续的提示信息

内容的提问来源于stack exchange，提问作者Uchenna Umeh