如何将JSON指定节点的数组转为对象（仅硬编码students与student节点）

原始输入JSON #

{
  "students": {
    "a": "qw",
    "b": "er",
    "student": [
      {
        "Id": "1",
        "details": {
         
          "q": "12",
          "w": "wer",
          "e": "rty",
          "r": "yui"
        }
      }
    ]
  }
}

期望输出JSON #

{
  "students": {
    "a": "qw",
    "b": "er",
    "student": {
      "Id": "1",
      "details": {
        "q": "12",
        "w": "wer",
        "e": "rty",
        "r": "yui"
      }
    }
  }
}

实现方法 #

JavaScript版本 #

// 原始JSON字符串
const originalJson = `{
  "students": {
    "a": "qw",
    "b": "er",
    "student": [
      {
        "Id": "1",
        "details": {
         
          "q": "12",
          "w": "wer",
          "e": "rty",
          "r": "yui"
        }
      }
    ]
  }
}`;

// 解析为JS对象
const data = JSON.parse(originalJson);

// 仅硬编码students和student节点，处理单元素数组转对象
if (data.students?.student instanceof Array && data.students.student.length === 1) {
  data.students.student = data.students.student[0];
}

// 转换回格式化后的JSON字符串
const transformedJson = JSON.stringify(data, null, 2);

console.log(transformedJson);

Python版本 #

import json

original_json = '''{
  "students": {
    "a": "qw",
    "b": "er",
    "student": [
      {
        "Id": "1",
        "details": {
         
          "q": "12",
          "w": "wer",
          "e": "rty",
          "r": "yui"
        }
      }
    ]
  }
}'''

# 解析为字典
data = json.loads(original_json)

# 处理指定节点：判断是否为单元素数组，是则转为对象
if isinstance(data.get('students', {}).get('student'), list) and len(data['students']['student']) == 1:
    data['students']['student'] = data['students']['student'][0]

# 转换回带格式的JSON字符串
transformed_json = json.dumps(data, indent=2)

print(transformed_json)

方案说明 #

• 仅硬编码students和student两个节点，不修改或依赖其他任何节点的结构，完全符合需求
• 逻辑简洁高效：先判断目标节点是否为数组且长度为1，满足条件则直接替换为数组的第一个元素
• 兼容性好：处理过程中保留了原始数据的所有其他字段和结构，不会破坏原有内容

内容的提问来源于stack exchange，提问作者techresearch