如何在Bazel中调整头文件包含路径，移除lib目录前缀？

Yes, you can achieve this without changing your source code by adjusting the includes attribute in your lib cc_library targets. Here's how to do it:

Step 1: Update lib/BUILD.bazel #

Add the includes = ["."] attribute to both lib1 and lib2 cc_library rules. This tells Bazel to add the lib/ directory to the include path for any target that depends on these libraries:

load("@rules_cc//cc:defs.bzl", "cc_library")

cc_library(
    name = "lib1",
    hdrs = glob(["lib1/**/*.hpp"]),
    srcs = glob(["lib1/**/*.cpp"]),
    copts = [
        ...,
    ],
    linkopts = [
        ...,
    ],
    visibility = [
        "//app:__pkg__",
        "//test:__pkg__",
    ],
    includes = ["."],  # Add this line
)

cc_library(
    name = "lib2",
    hdrs = glob(["lib2/**/*.hpp"]),
    srcs = glob(["lib2/**/*.cpp"]),
    copts = [
        ...,
    ],
    linkopts = [
        ...,
    ],
    visibility = [
        "//app:__pkg__",
        "//test:__pkg__",
    ],
    includes = ["."],  # Add this line
)

Step 2: Restore original include paths in main.cpp #

Revert to your team's preferred syntax:

#include "lib1/lib1.hpp"
#include "lib2/lib2.hpp"

Why this works #

The includes attribute propagates the lib/ directory as an include path to dependent targets (like your app binary). When compiling main.cpp, Bazel automatically adds -I<workspace-root>/lib to the compiler flags, letting the preprocessor resolve lib1/lib1.hpp to the actual file at lib/lib1/lib1.hpp.

Cleanup (if needed) #

If you added manual include path flags (such as -I../ or -Ilib/) to your app target's copts, you can remove them now—this approach handles include paths in a modular, dependency-aware way.

内容的提问来源于stack exchange，提问作者OpticalMagician