如何实现Python函数仅在float值为1.0时返回True，其余按规则返回？

Hey there! Let's adjust your function to meet the exact requirements you laid out. The original bool(floatVal) line converts any non-zero float to True and zero to False, which isn't what you want—we need strict checks for exactly 1.0 and exactly 0.0, with None returned otherwise.

Modified Code #

Here's the updated version of your function, with the key change in line 5:

import random 

def choice(): 
    floatVal = round(random.uniform(0,1), 1) 
    # Strict value matching as requested
    return True if floatVal == 1.0 else False if floatVal == 0.0 else None

print(choice())  # Added parentheses for Python 3 compatibility

How It Works #

• We use exact equality checks (==) to match floatVal against 1.0 and 0.0—this ensures we only trigger the return values when the value is perfectly matched, no implicit type conversion or fuzzy matching.
• If floatVal is exactly 1.0, we return True.
• If it's exactly 0.0, we return False.
• For any other value (like 0.1, 0.5, etc.), we return None as specified.

Alternative Explicit If-Else Structure #

If you prefer a more verbose (but equally strict) approach, you can write line 5 like this instead—same logic, just laid out more clearly:

if floatVal == 1.0:
    return True
elif floatVal == 0.0:
    return False
else:
    return None

Either way, both implementations stick to strict value matching and meet all your requirements perfectly.

内容的提问来源于stack exchange，提问作者Ashish Kumar