Hey Ibrahim, let's fix this issue step by step!

The Core Problem #

The root cause here is that Python's input() function always returns a string, no matter what the user types. So when you check type(number), it will always be <class 'str'>—that's why your first two conditionals never trigger, and the code jumps straight to the else block.

How to Check if Input is Integer or Float? #

You need to first attempt to convert the input string into a numeric type, while handling cases where the input isn't a valid number. Here are two reliable approaches tailored to your converter needs:

Approach 1: Try Integer Conversion First, Then Float

This method prioritizes checking for integers first (even if the user enters 2.0, we can treat it as an integer for hex formatting):

user_input = input("Please input your number...... \n")

try:
    # Try converting to integer first
    num = int(user_input)
    print(f"Entered number is integer: {num}, and its hexadecimal is: {hex(num)}")
except ValueError:
    # If integer conversion fails, try float
    try:
        num = float(user_input)
        print(f"Entered number is float: {num}, and its hexadecimal is: {float.hex(num)}")
    except ValueError:
        # Neither conversion worked—invalid input
        print("You entered an invalid number")

Approach 2: Convert to Float First, Then Check for Whole Numbers

This approach converts to float first, then uses the is_integer() method to identify whole numbers and format them as integers:

user_input = input("Please input your number...... \n")

try:
    num = float(user_input)
    if num.is_integer():
        # Convert to int for proper integer hex formatting
        num_int = int(num)
        print(f"Entered number is integer: {num_int}, and its hexadecimal is: {hex(num_int)}")
    else:
        print(f"Entered number is float: {num}, and its hexadecimal is: {float.hex(num)}")
except ValueError:
    print("You entered an invalid number")

Key Notes #

• We use try-except blocks to safely handle invalid inputs (like text that can't be converted to a number). This prevents the program from crashing if the user enters something non-numeric.
• float.hex() returns the hexadecimal representation of a float, while hex() works for integers—both are exactly what you need for your converter.

内容的提问来源于stack exchange，提问作者Ibrahim