如何将形状与位置可变的Dask delayed对象赋值给Dask数组
问题:动态形状的小型Dask数组赋值到大型数组指定区域
需要将多个**形状未知(延迟获取)**的小型Dask数组,赋值到提前知晓形状的大型Dask数组的非顺序2D位置。直接使用dask.delayed包装小型数组和位置时触发错误,而使用普通Dask数组则可正常运行。
示例代码
import dask.array as da import dask ## 初始化大型数组 big_array = da.zeros([5, 6]) # 提前知晓该形状 # 模拟小型数组 aa_shape = dask.delayed((2,3)) # 无法提前知晓该形状 aa = dask.delayed(1 * da.ones(aa_shape)) aa_loc = dask.delayed((slice(0,2), slice(0,3))) # 无法提前知晓该位置 bb_shape = dask.delayed((3,3)) bb = dask.delayed(2 * da.ones(bb_shape)) bb_loc = dask.delayed((slice(0,3), slice(3,6))) cc_shape = dask.delayed((3,3)) cc = dask.delayed(3 * da.ones(cc_shape)) cc_loc = dask.delayed((slice(2,5), slice(0,3))) dd_shape = dask.delayed((2,3)) dd = dask.delayed(4 * da.ones(dd_shape)) dd_loc = dask.delayed((slice(3,5), slice(3,6))) # 手动填充大型数组 big_array[aa_loc] = aa big_array[bb_loc] = bb big_array[cc_loc] = cc big_array[dd_loc] = dd big_array.compute()
理想输出
array([[1., 1., 1., 2., 2., 2.], [1., 1., 1., 2., 2., 2.], [3., 3., 3., 2., 2., 2.], [3., 3., 3., 4., 4., 4.], [3., 3., 3., 4., 4., 4.]])
报错信息
--------------------------------------------------------------------------- TypeError Traceback (most recent call last) Input In [7], in <cell line: 21>() 18 locs = [aa_loc, bb_loc, cc_loc, dd_loc] 20 # Manually populate big array ---> 21 big_array[aa_loc] = aa 22 big_array[bb_loc] = bb 23 big_array[cc_loc] = cc File ~/.conda-envs/daskenv202301/lib/python3.9/site-packages/dask/array/core.py:1893, in Array.__setitem__(self, key, value) 1890 value = asanyarray(value) 1892 out = "setitem-" + tokenize(self, key, value) -> 1893 dsk = setitem_array(out, self, key, value) 1895 meta = meta_from_array(self._meta) 1896 if np.isscalar(meta): File ~/.conda-envs/daskenv202301/lib/python3.9/site-packages/dask/array/slicing.py:1754, in setitem_array(out_name, array, indices, value) 1752 array_shape = array.shape 1753 value_shape = value.shape -> 1754 value_ndim = len(value_shape) 1756 # Reformat input indices 1757 indices, implied_shape, reverse, implied_shape_positions = parse_assignment_indices( 1758 indices, array_shape 1759 ) File ~/.conda-envs/daskenv202301/lib/python3.9/site-packages/dask/delayed.py:591, in Delayed.__len__(self) 589 def __len__(self): 590 if self._length is None: -> 591 raise TypeError("Delayed objects of unspecified length have no len()") 592 return self._length TypeError: Delayed objects of unspecified length have no len()
解决方案
错误根源是Dask数组的赋值操作需要提前知晓形状和位置的元数据,而dask.delayed对象无法提供这些元信息(无法直接获取len())。以下是三种可行思路:
方法1:提前解析延迟的形状和位置
如果形状、位置的计算开销低,可以先compute()得到实际值,再用普通Dask数组执行赋值:
import dask.array as da import dask # 初始化大型数组 big_array = da.zeros([5, 6]) # 解析延迟的形状和位置 aa_shape = dask.delayed((2,3)).compute() aa = 1 * da.ones(aa_shape) aa_loc = dask.delayed((slice(0,2), slice(0,3))).compute() bb_shape = dask.delayed((3,3)).compute() bb = 2 * da.ones(bb_shape) bb_loc = dask.delayed((slice(0,3), slice(3,6))).compute() cc_shape = dask.delayed((3,3)).compute() cc = 3 * da.ones(cc_shape) cc_loc = dask.delayed((slice(2,5), slice(0,3))).compute() dd_shape = dask.delayed((2,3)).compute() dd = 4 * da.ones(dd_shape) dd_loc = dask.delayed((slice(3,5), slice(3,6))).compute() # 执行赋值 big_array[aa_loc] = aa big_array[bb_loc] = bb big_array[cc_loc] = cc big_array[dd_loc] = dd print(big_array.compute())
方法2:用延迟函数封装全部赋值逻辑
如果形状和位置必须延迟计算(依赖其他重计算),可以将整个赋值逻辑封装为延迟函数,最后转为Dask数组:
import dask.array as da import dask import numpy as np def fill_big_array(): # 内部用numpy完成所有动态赋值逻辑 big_np = np.zeros([5,6]) # 模拟动态获取形状、数组和位置 aa_shape = (2,3) # 替换为实际延迟计算逻辑 aa = 1 * np.ones(aa_shape) aa_loc = (slice(0,2), slice(0,3)) big_np[aa_loc] = aa bb_shape = (3,3) bb = 2 * np.ones(bb_shape) bb_loc = (slice(0,3), slice(3,6)) big_np[bb_loc] = bb cc_shape = (3,3) cc = 3 * np.ones(cc_shape) cc_loc = (slice(2,5), slice(0,3)) big_np[cc_loc] = cc dd_shape = (2,3) dd = 4 * np.ones(dd_shape) dd_loc = (slice(3,5), slice(3,6)) big_np[dd_loc] = dd return big_np # 将延迟函数转为Dask数组,指定输出形状和类型 big_array = da.from_delayed(dask.delayed(fill_big_array()), shape=(5,6), dtype=np.float64) print(big_array.compute())
方法3:分块处理赋值(适合分布式场景)
如果大型数组采用分块存储,可针对每个分块编写赋值逻辑,用map_blocks执行:
import dask.array as da import numpy as np def assign_block(block, block_info): # 获取当前分块在大型数组中的起始位置 block_start = block_info[0]['chunk-location'] # 根据分块位置匹配对应小型数组的赋值逻辑 if block_start == (0,0): # 填充aa和bb的部分区域 block[:2, :3] = 1 * np.ones((2,3)) block[:2, 3:] = 2 * np.ones((2,3)) elif block_start == (0,1): # 填充bb的剩余区域 block[:3, :] = 2 * np.ones((3,3)) elif block_start == (1,0): # 填充cc的区域 block[:, :3] = 3 * np.ones((3,3)) elif block_start == (1,1): # 填充cc的剩余区域和dd的区域 block[:2, :3] = 3 * np.ones((2,3)) block[:2, 3:] = 4 * np.ones((2,3)) return block # 初始化分块的大型数组 big_array = da.zeros([5,6], chunks=(2,3)) # 对每个分块应用赋值函数 big_array = big_array.map_blocks(assign_block, meta=np.float64) print(big_array.compute())
内容的提问来源于stack exchange,提问作者rybchuk
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