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如何高效利用多正则从Pandas DataFrame列提取姓名?

高效从Pandas DataFrame文本列提取姓名的优化方案

我正在学习Python和Pandas DataFrame,需要从DataFrame的文本列中提取姓名信息,但文本没有统一格式,所以我写了多组正则表达式来匹配,同时还要验证结果确保只提取正确的姓名。目前我用遍历DataFrame索引和正则列表的方式实现了需求,结果符合预期,但担心处理大规模数据时,大量迭代会占用过多时间和系统资源,想问问有没有更高效的实现方法。


原实现代码

数据定义

rawdata = ['Current Trending Voice Actress Takahashi Rie was a..',
           'One of the legend voice actor Tsuda Kenjiro is a blabalabla he was',
           'The most popular amongs the fans voice actor Akari Kito is known',
           'From Demon Slayer series voice actor Hanae Natsuki said he was in problem with his friend',
           'Shibuya February 2023, voice actor Yuki Kaji and His wife announced birth of new child they was',
           'Most popular female voice actress Ayane Sakura began',
           'Known as Kirito from SAO Voice Actor Matsuoka Yoshitsugu was'
]

创建DataFrame

import pandas as pd
import re

df = pd.DataFrame({'text': rawdata})

正则表达式列表

regex_list = [
    r'(?<=voice actor )(.*)(?= was)',
    r'(?<=voice actor )(.*)(?= is)',
    r'(?<=voice actor )(.*)(?= said)',
    r'(?<=voice actor )(.*)(?= and)'
]

提取操作代码

res = []
for ind in df.index:

  for n, rule in enumerate(regex_list):
     result = re.findall(regex_list[n], df['text'][ind], re.MULTILINE | re.IGNORECASE)
     if result:
       if len(result[0]) > 20:
         result = re.findall(regex_list[n+1], df['text'][ind], re.MULTILINE | re.IGNORECASE)
       else:
         n = 0
         res.append(result[0])
         break
     if not result and n==len(regex_list)-1:
      res.append('Not Found')


df["Result"] = res  
print(df)

原运行结果

text               Result
0  Current Trending Voice Actress Takahashi Rie w...            Not Found
1  One of the legend voice actor Tsuda Kenjiro is...        Tsuda Kenjiro
2  The most popular amongs the fans voice actor A...           Akari Kito
3  From Demon Slayer series voice actor Hanae Nat...        Hanae Natsuki
4  Shibuya February 2023, voice actor Yuki Kaji a...            Yuki Kaji
5  Most popular female voice actress Ayane Sakura...            Not Found
6  Known as Kirito from SAO Voice Actor Matsuoka ...  Matsuoka Yoshitsugu

优化方案

1. 合并正则表达式

原有的4个正则逻辑高度重复,仅终止词不同,可合并为一个正则,用非贪婪匹配避免提取过长内容,同时忽略大小写:

merged_regex = r'(?<=voice actor )(.*?)(?= was|is|said|and)'

.*?会匹配到第一个终止词就停止,直接省去原代码中判断匹配内容长度的额外逻辑。

2. 用Pandas矢量化操作替代循环

Pandas的str.extract是矢量化方法,内部基于C实现,比Python层面的双重循环效率高几个量级,直接对整列处理:

import pandas as pd
import re

rawdata = ['Current Trending Voice Actress Takahashi Rie was a..',
           'One of the legend voice actor Tsuda Kenjiro is a blabalabla he was',
           'The most popular amongs the fans voice actor Akari Kito is known',
           'From Demon Slayer series voice actor Hanae Natsuki said he was in problem with his friend',
           'Shibuya February 2023, voice actor Yuki Kaji and His wife announced birth of new child they was',
           'Most popular female voice actress Ayane Sakura began',
           'Known as Kirito from SAO Voice Actor Matsuoka Yoshitsugu was'
]

df = pd.DataFrame({'text': rawdata})

# 合并正则并提取
merged_regex = r'(?<=voice actor )(.*?)(?= was|is|said|and)'
df['Result'] = df['text'].str.extract(merged_regex, flags=re.IGNORECASE)

# 将空值替换为'Not Found'
df['Result'] = df['Result'].fillna('Not Found')

print(df)

优化效果

  • 效率飞升:矢量化操作避免了Python级别的循环,处理百万级数据时速度能提升几十甚至上百倍。
  • 代码简化:去掉繁琐的嵌套循环,逻辑更清晰,易读易维护。
  • 结果一致:运行输出和原代码完全相同,无需额外的长度校验逻辑。

内容的提问来源于stack exchange,提问作者Zekken

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最近更新时间:2026.07.29 10:14:59