如何用JS移除WebVTT文件中第一个时间戳前的所有内容？

你需要移除WebVTT文件内第一个时间戳之前的所有内容，但之前用的正则表达式.replace(/(.*)\s+1/gmi, '')会误删首行的“1”，目标是保留“1”作为文件首行，仅删除其之前的内容。

原WebVTT文件内容 #

WEBVTT

1
00:00:00.080 --> 00:00:05.930
Lorem Ipsum is simply dummy text of the printing and typesetting industry. 

2
00:00:05.930 --> 00:00:07.430
Lorem Ipsum is simply dummy text of the printing and typesetting industry. 

3
00:00:07.430 --> 00:00:13.130
Lorem Ipsum is simply dummy text of the printing and typesetting industry. 

期望处理后内容 #

1
00:00:00.080 --> 00:00:05.930
Lorem Ipsum is simply dummy text of the printing and typesetting industry. 

2
00:00:05.930 --> 00:00:07.430
Lorem Ipsum is simply dummy text of the printing and typesetting industry. 

3
00:00:07.430 --> 00:00:13.130
Lorem Ipsum is simply dummy text of the printing and typesetting industry. 

正确正则表达式及用法 #

使用以下正则表达式进行替换，可精准匹配并删除“1”之前的所有内容，同时保留“1”行：

const cleanedContent = webvttContent.replace(/^[\s\S]*?(?=^1$)/m, '');

正则说明

• ^：开启多行模式后，匹配字符串开头或行开头
• [\s\S]*?：非贪婪匹配任意字符（含换行），避免过度匹配后续内容
• (?=^1$)：正向预查，确保匹配截止到单独一行的“1”之前，不会包含“1”本身

内容的提问来源于stack exchange，提问作者maTe