使用Lodash按条件去除对象数组中的重复项

给定对象数组：

[
    {id:1,name:'abc',path:'canvas.abc'},
    {id:1,name:'abc',path:'public.abc'},
    {id:2,name:'def',path:'supply.def'},
    {id:3,name:'xyz',path:'package.xyz'}
]

要实现按ID去重且优先保留path包含canvas的对象，仅用Lodash可以通过groupBy+map+find的组合完成：

const _ = require('lodash');

const originalArray = [
    {id:1,name:'abc',path:'canvas.abc'},
    {id:1,name:'abc',path:'public.abc'},
    {id:2,name:'def',path:'supply.def'},
    {id:3,name:'xyz',path:'package.xyz'}
];

const result = _.map(_.groupBy(originalArray, 'id'), group => {
    // 优先查找分组内path包含canvas的对象
    const targetItem = _.find(group, item => _.includes(item.path, 'canvas'));
    // 找到就留它，没找到就取分组第一个元素
    return targetItem || group[0];
});

console.log(result);

逻辑说明 #

• _.groupBy先把数组按id分组，相同ID的对象会被归为一组
• 遍历每个分组时，用_.find精准定位组内符合path含canvas的对象
• 确保每个ID仅保留一个对象，且优先保留符合路径要求的项

运行后输出结果：

[
    {id:1,name:'abc',path:'canvas.abc'},
    {id:2,name:'def',path:'supply.def'},
    {id:3,name:'xyz',path:'package.xyz'}
]

内容的提问来源于stack exchange，提问作者Sam David