调用GeoPoint类get_distance方法时提示缺少point参数的问题

核心错误原因 #

你代码里的geo = GeoPoint没有实例化类，只是把类本身赋值给了变量。当直接通过类调用实例方法get_distance时，Python不会自动传入self参数——此时你传的point3会被当作self，而原本需要的point参数就缺失了，所以报出"missing 1 required positional argument: 'point'"的错误。

具体修复步骤 #

1. 修复方法调用方式 #

实例方法必须通过类的实例调用，Python才会自动把实例作为self参数传入。比如你要计算point3和point1的距离，应该用point1.get_distance(point3)，而不是用未实例化的类调用。

2. 修正get_distance的逻辑问题 #

你当前的get_distance方法里，先用实例的坐标赋值了lat1、lon1等变量，随后又用input重新覆盖了这些值，完全浪费了实例的坐标数据。应该删除多余的input代码，直接使用实例存储的经纬度计算距离，并且返回计算结果（方便后续比较）。修改后的方法如下：

def get_distance(self, point): 
    lat1 = radians(self.lat)
    lon1 = radians(self.lon)
    lat2 = radians(point.lat)
    lon2 = radians(point.lon)

    # 计算两点间球面距离
    dist = 6371.01 * acos(sin(lat1)*sin(lat2) + cos(lat1)*cos(lat2)*cos(lon1 - lon2))
    return dist

3. 修复其他语法/逻辑问题 #

• dist = ()是不可变元组，无法进行dist[1]这类赋值操作，改成字典或列表（比如dist = {}）存储不同点的距离。
• point3 = GeoPoint(latlon, Loc)会把元组latlon直接传给lat参数，导致lon用默认值0，正确写法是point3 = GeoPoint(*latlon, Loc)，用拆包方式传递经纬度。
• 调用point2.point赋值时，建议加上括号明确元组：point2.point = (23.4567, -213.456)。

修改后的完整调用脚本 #

from GeoPoint import GeoPoint

def doanother():
    '''Asks user if they want to do another and returns True or False'''
    usr_response = input("Do another (y/n)? ")
    another = usr_response.strip()[0].lower() == 'y'
    return another

while True:
    try:
        dist = {}
        point1 = GeoPoint(12.3456, -123.4567, 'Loc1')
        point2 = GeoPoint()
        point2.point = (23.4567, -213.456)
        point2.description = 'Loc2'

        # 获取用户坐标
        choice = input('Enter the lat and lon of your location (format: lat, lon): ')
        latlon = tuple(map(float, choice.split(', ')))
        print("Your coordinates:", latlon)

        Loc = input('Enter your location name: ')

        # 初始化用户位置实例
        point3 = GeoPoint(*latlon, Loc)
        # 计算到两个预设点的距离
        dist[point1.description] = point1.get_distance(point3)
        dist[point2.description] = point2.get_distance(point3)

        # 找出最短距离及对应地点
        shortest_dist = min(dist.values())
        closest_loc = [loc for loc, distance in dist.items() if distance == shortest_dist][0]

        print(f'The shortest distance is {shortest_dist:.2f}km, to {closest_loc}')  
    except Exception as e:
        print(f'Error: {e}')

    if not doanother():
        break

内容的提问来源于stack exchange，提问作者Scott Bing