隐藏短语游戏Java程序：实现大小写不敏感的字母匹配

要实现忽略大小写的字母匹配，只需修改字符比较逻辑，同时保留原短语的大小写格式，以下是具体方案：

关键修改点 #

• 将字符比较逻辑改为统一转成小写（或大写）后判断相等，确保输入的大小写不影响匹配结果
• 匹配成功时，使用原短语中的字符填充，保证显示内容和原短语的大小写一致

修改后的完整代码 #

package main;
import java.util.*;

public class Main {

    public static void main(String[] args) 
    {
        int choice;
        Scanner input = new Scanner(System.in);

        System.out.print("Please enter your name: ");
        String name = input.nextLine();
        Player player = new Player();
        player.setName(name);
        
        do 
        {
            System.out.println("--------------------------------");
            System.out.println("Welcome to the Hidden Word Game!");

            game(player);
            System.out.println("--------------------------------");
            System.out.println("Would you like to play again?\n1: Yes\n2: No");
            System.out.print("Enter your choice: ");
            choice = input.nextInt();
            // 处理nextInt后的换行符，避免后续nextLine读取空字符串
            input.nextLine();
        } while (choice != 2);
    }
    
    public static void game(Player player) 
    {
        
        Scanner input = new Scanner(System.in);
        
        String[] wordList = new String[] {"cruise ship", "soft drink", "National Football League", "New York", "little girl"};
        String randomWord = wordList[(int)(Math.random() * wordList.length)];

        StringBuilder word = new StringBuilder();
        for (int i = 0; i < randomWord.length(); i++) 
        {
            if (randomWord.charAt(i) == ' ') {
                word.append(' ');
            } else {
                word.append('*');
            }
        }

        char[] hiddenWord = randomWord.toCharArray();

        System.out.println("--------------------------------");
        while(true) 
        {
            System.out.println("Secrect Word :" + word);
            System.out.print("Guess one or more letters : ");
            player.setAttempts();
            boolean correct = false;

            char [] guess = input.nextLine().toCharArray();

            for(int i = 0 ; i < hiddenWord.length; i++) 
            {
                for (int j = 0; j < guess.length; j++)
                {
                    // 修改：统一转小写后比较，忽略大小写差异
                    if (Character.toLowerCase(guess[j]) == Character.toLowerCase(hiddenWord[i])) 
                    {
                        // 修改：使用原短语字符，保留原始大小写
                        word.setCharAt(i, hiddenWord[i]);
                        correct = true;
                    }
                }

            }
            if (!correct) 
            {
                System.out.println("You chose incorrect");
            } else {
                System.out.println("You chose correct");
            }

            System.out.println("--------------------");

            if (randomWord.equals(word.toString())) 
            {
                System.out.println("Congratulations " + player.getName() + " You Guessed The Hidden Word: " + randomWord);
                System.out.println("It took you " + player.getAttempts() + " attempts.");                            
                break;
            }
        }
    }
}

额外优化说明 #

原代码中input.nextInt()后直接调用input.nextLine()会读取到空字符串，因此添加input.nextLine();处理换行符，避免游戏循环中出现异常。

内容的提问来源于stack exchange，提问作者Myrdock