如何将网格行输出为单个字符串而非独立字符?Python代码修改咨询
rows Function to Match Your Expected Output Got it, let's work through this. Your current code is just taking each sublist from the input and adding it directly to your result list—so it's essentially returning a string version of the original grid. What you need instead is to join all the characters in each sublist into a single string, then wrap that collection of strings in an extra outer list (like your expected output specifies).
Here's a modified version of your code that sticks to your original loop structure, with the necessary tweaks:
def rows(test): r = [] for x in test: # Join the characters in each row into one continuous string r.append(''.join(x)) # Wrap the list of joined strings in an outer list, then convert to string return str([r])
If you prefer a more concise Pythonic approach using a list comprehension, this does the exact same thing:
def rows(test): joined_rows = [''.join(row) for row in test] return str([joined_rows])
Let's break down the key changes:
''.join(x): This takes a list of characters (like["r","a","w","b","i","t"]) and concatenates them into a single string ('rawbit').- Wrapping in
[r]: Your expected output has an extra outer list around the collection of row strings, so we need to nest our list of joined strings inside another list before converting to a string.
When you run this modified rows(test) with your sample grid, you'll get exactly the output you want:[['rawbit','xayzch','pqbeie','trsbog', 'uwxvit', 'nmrwot']]
内容的提问来源于stack exchange,提问作者Nutnicha

