如何在VS Code中仅高亮Python函数定义而非函数调用

解决办法 #

问题核心是entity.name.function这个作用域范围太宽泛，不仅匹配函数定义，还会覆盖到函数调用里的相关符号。要实现只高亮函数定义，得用更精准的作用域。

1. 用VS Code工具查精准作用域

打开VS Code，按Ctrl+Shift+P（Windows/Linux）或Cmd+Shift+P（Mac），输入Inspect Editor Tokens and Scopes并回车。把光标放在planetorbit上，查看弹出面板里的作用域链，找到最精准的那个（一般是最底层、和函数定义直接绑定的作用域，比如meta.function-definition entity.name.function或者带语言后缀的entity.name.function.lua）。

2. 修改配置文件

• 先关闭语义高亮（避免它干扰自定义规则）：把"editor.semanticHighlighting.enabled"改成false。
• 替换原来的entity.name.function规则，用上刚才查到的精准作用域。

修改后的示例配置（假设查到的精准作用域是meta.function-definition entity.name.function）：

"editor.semanticHighlighting.enabled": false,
"editor.tokenColorCustomizations": {
    "keywords": "#FF8000",
    "comments": "#DD0000",
    "strings": "#02ff02dc",
    "variables": "#FFFFFF",
    "functions": "#FFFFFF",
    "numbers": "#FFFFFF",
    "textMateRules": [
        {"scope": "variable.parameter",
        "settings": {"foreground": "#FFFFFF"}},
        {"scope": "meta",
        "settings": {"foreground": "#FFFFFF"}},
        {"scope": "support.function",
        "settings": {"foreground": "#5e5eff"}},
        {"scope": "keyword.operator",
        "settings": {"foreground": "#FFFFFF"}},
        {"scope": "punctuation.separator",
        "settings": {"foreground": "#FFFFFF"}},
        {"scope": "meta.function-definition entity.name.function",
        "settings": {"foreground": "#5E5EFF"}},
        {"scope": "entity.name.function-call",
        "settings": {"foreground": "#FFFFFF"}},
    ]
},
"workbench.colorCustomizations": {
    "editor.selectionBackground": "#7E7E7E",
    "editor.background": "#002240",
    "editorBracketHighlight.foreground1": "#FFFFFF",
    "editorBracketHighlight.foreground2": "#FFFFFF",
    "editorBracketHighlight.foreground3": "#FFFFFF",
},
"workbench.colorTheme": "Abyss",

3. 验证效果

保存配置后重启VS Code，查看代码高亮是否符合预期。如果还是有问题，再用Inspect工具检查其他元素的作用域，调整规则优先级。

内容的提问来源于stack exchange，提问作者You Theone