如何在for循环中跳过已匹配项？解决Wordle类游戏重复字母判定问题

项目背景 #

我正在开发一款类似Wordle的简易5字母猜词游戏，核心逻辑：

• 程序随机获取一个5字母单词
• 用户输入猜测单词后，反馈字母是否存在于目标单词中，以及是否处于正确位置

问题描述 #

当目标单词包含重复字母时，代码会错误地向用户反馈过多该字母。核心原因是当前代码会用用户输入的每个字母遍历整个目标单词，导致匹配过程重复执行——比如示例中会向反馈列表添加4个O。

我需要找到一种在循环中跳过已匹配字母的方法。尝试过一个临时解决方案，但它无法处理包含三个相同字母的单词：

if len(userInput) < len(letter):
    deleted = []
    for i in range(len(letter)):
        l = i + 1
        if letter[i] == letter[l]:
            deleted.append(letter[i])
            del letter[i]
    if len(userInput) > len(letter):
        for i in range(len(deleted)):
            l = i + 1
            if deleted[i] == deleted[l]:
                del letter[i]
        letter.append(deleted)

这个方案只是临时删除部分重复项，无法彻底解决问题。

完整代码 #

from random_word import Wordnik
wordnik_service = Wordnik()

truth = True

#grabs a random word
randWord = wordnik_service.get_random_word(minLength=5, maxLength=5)

#starts the while loop until the word has been solved
while truth == True:
    #creates an input in the terminal for the user to submit there word
    userInput = input("Guess a 5-letter word: ")
    #defining variables and lists
    letter = []
    trueLett = []
    same = False
    #create for loops to cycle through the user inputed word and the random word to find letters that match
    for i in range(len(userInput)):
        for l in range(len(randWord)):
            #checks if the letters are the same value
            if randWord[l] == userInput[i]:
                #checks if the letter are both in the same position
                if l == i:
                    same = True
                    trueLett.append(randWord[l])
                #checks if the letter isn't in the same position
                elif l != i:
                    letter.append(randWord[l])
            l+=1   
        i+=1
        
        #we don't talk about this italian dish that was cooked by a toddler
        if len(userInput) < len(letter):
            deleted = []
            for i in range(len(letter)):
                l = i + 1
                if letter[i] == letter[l]:
                    deleted.append(letter[i])
                    del letter[i]
            if len(userInput) > len(letter):
                for i in range(len(deleted)):
                    l = i + 1
                    if deleted[i] == deleted[l]:
                        del letter[i]
                letter.append(deleted)
              
    if userInput == randWord:
        print("Correct")
        truth = False
    elif userInput == 'Lose':
        print(randWord)
    elif len(userInput) > 5 or len(userInput) < 5:
        print('The word is 5-letters. Please try again')
    else:
        print("Incorrect. Try again")
        if same == True:   
            print("These letter/s: " + str(trueLett) + " are in the correct place")
        if len(letter) != 0:
            print("These letter/s: " + str(letter) + " are in the word")

希望能得到可行的解决方案，感谢帮助。

内容的提问来源于stack exchange，提问作者Noah Robb