Python中使用list.remove移除指定字符串报错ValueError的问题排查请求
解决列表移除字符串时的ValueError问题
嘿,我一眼就看出问题出在哪了——你用错了split()的用法!
你原来的代码里,y = x.split()是默认按空格分割字符串,但你的每个uri都是连续的长字符串(比如spotify:playlist:37i9dQZF1DXcBWIGoYBM5M),根本没有空格,所以y其实是一个只包含原完整字符串的单元素列表。这时候你调用y.remove('spotify:playlist:'),自然会报错,因为列表里根本没有这个单独的前缀字符串,只有一整个长串。
给你几个简单高效的解决办法,都能拿到你想要的播放列表ID:
方法1:字符串替换(最直观)
直接把前缀spotify:playlist:替换成空字符串就行,代码简洁易懂:
spotify_data = {'uri':['spotify:playlist:37i9dQZF1DXcBWIGoYBM5M', 'spotify:playlist:37i9dQZF1DX0XUsuxWHRQd', 'spotify:playlist:37i9dQZF1DX1lVhptIYRda', 'spotify:playlist:37i9dQZF1DX10zKzsJ2jva', 'spotify:playlist:37i9dQZF1DX4JAvHpjipBk', 'spotify:playlist:37i9dQZF1DX4sWSpwq3LiO', 'spotify:playlist:37i9dQZF1DX4SBhb3fqCJd', 'spotify:playlist:37i9dQZF1DWXRqgorJj26U', 'spotify:playlist:37i9dQZF1DX4dyzvuaRJ0n', 'spotify:playlist:37i9dQZF1DXcF6B6QPhFDv', 'spotify:playlist:37i9dQZF1DWXJfnUiYjUKT']} ID = [] prefix = 'spotify:playlist:' for x in spotify_data['uri']: if prefix in x: playlist_id = x.replace(prefix, '') ID.append(playlist_id) print(ID)
方法2:字符串切片(性能最优)
因为前缀的长度是固定的,直接截取前缀之后的部分,速度更快:
spotify_data = {'uri':['spotify:playlist:37i9dQZF1DXcBWIGoYBM5M', 'spotify:playlist:37i9dQZF1DX0XUsuxWHRQd', 'spotify:playlist:37i9dQZF1DX1lVhptIYRda', 'spotify:playlist:37i9dQZF1DX10zKzsJ2jva', 'spotify:playlist:37i9dQZF1DX4JAvHpjipBk', 'spotify:playlist:37i9dQZF1DX4sWSpwq3LiO', 'spotify:playlist:37i9dQZF1DX4SBhb3fqCJd', 'spotify:playlist:37i9dQZF1DWXRqgorJj26U', 'spotify:playlist:37i9dQZF1DX4dyzvuaRJ0n', 'spotify:playlist:37i9dQZF1DXcF6B6QPhFDv', 'spotify:playlist:37i9dQZF1DWXJfnUiYjUKT']} ID = [] prefix = 'spotify:playlist:' prefix_length = len(prefix) for x in spotify_data['uri']: # 用startswith判断比in更严谨,确保前缀是在开头 if x.startswith(prefix): playlist_id = x[prefix_length:] ID.append(playlist_id) print(ID)
方法3:指定分隔符的split(如果你非要用split的话)
如果坚持想用split,得指定用spotify:playlist:作为分隔符,然后取分割后的第二个元素:
spotify_data = {'uri':['spotify:playlist:37i9dQZF1DXcBWIGoYBM5M', 'spotify:playlist:37i9dQZF1DX0XUsuxWHRQd', 'spotify:playlist:37i9dQZF1DX1lVhptIYRda', 'spotify:playlist:37i9dQZF1DX10zKzsJ2jva', 'spotify:playlist:37i9dQZF1DX4JAvHpjipBk', 'spotify:playlist:37i9dQZF1DX4sWSpwq3LiO', 'spotify:playlist:37i9dQZF1DX4SBhb3fqCJd', 'spotify:playlist:37i9dQZF1DWXRqgorJj26U', 'spotify:playlist:37i9dQZF1DX4dyzvuaRJ0n', 'spotify:playlist:37i9dQZF1DXcF6B6QPhFDv', 'spotify:playlist:37i9dQZF1DWXJfnUiYjUKT']} ID = [] for x in spotify_data['uri']: if 'spotify:playlist:' in x: # 指定分隔符分割后,得到['', '播放列表ID'] parts = x.split('spotify:playlist:') playlist_id = parts[1] ID.append(playlist_id) print(ID)
这三种方法都能得到你想要的结果:['37i9dQZF1DXcBWIGoYBM5M', '37i9dQZF1DX0XUsuxWHRQd', ...]
内容的提问来源于stack exchange,提问作者Stackbeans
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