如何计算游戏角色从点1到点2的旋转角度？（C#游戏开发作业求助）

我正在完成Coursera上的C#游戏开发课程作业，任务是计算两点间距离，以及游戏角色从第一点移动到第二点需要的旋转角度。现在卡在旋转角度的计算上，不知道怎么用现有数值构建求解方程。以下是我目前写的代码：

using System;

namespace ProgrammingAssignment2
{
    // IMPORTANT: Only add code in the section
    // indicated below. The code I've provided
    // makes your solution work with the 
    // automated grader on Coursera

    /// <summary>
    /// Programming Assignment 2
    /// </summary>
    class Program
    {
        // x and y coordinates for points
        static float point1X;
        static float point1Y;
        static float point2X;
        static float point2Y;

        /// <summary>
        /// Programming Assignment 2
        /// </summary>
        /// <param name="args">command-line args</param>
        static void Main(string[] args)
        {
            // loop while there's more input
            string input = Console.ReadLine();
            while (input[0] != 'q')
            {
                // extract point coordinates from string
                GetInputValuesFromString(input);

                // Add your code between this comment
                // and the comment below. You can of
                // course add more space between the
                // comments as needed

                int point1X = 5;
                int point2X = 4;

                int deltaX = -1;
                int deltaY = -1;

                int point1Y = 5;
                int point2Y = 4;

                int angle2 = -135;

                float hypotnuse = (deltaX * 2 + deltaY * 2);

                float distance = (float)Math.Sqrt((Math.Pow(point2X - point1X, 2) + Math.Pow(point2Y - point1X, 2)));

                float angle = (float)Math.Atan2(point2X - point1X, point2Y - point1Y);

                float CumulationofDistanceandHyp = ((distance * 2 + hypotnuse * 2));

                Console.Write( distance + " and " + angle);

                Console.Write("The distance between delta Y and X is  " + hypotnuse);

                Console.Write("Then what is " + CumulationofDistanceandHyp);

                // Don't add or modify any code below
                // this comment
                input = Console.ReadLine();
            }
        }

        /// <summary>
        /// Extracts point coordinates from the given input string
        /// </summary>
        /// <param name="input">input string</param>
        static void GetInputValuesFromString(string input)
        {
            // extract point 1 x
            int spaceIndex = input.IndexOf(' ');
            point1X = float.Parse(input.Substring(0, spaceIndex));

            // move along string and extract point 1 y
            input = input.Substring(spaceIndex + 1);
            spaceIndex = input.IndexOf(' ');
            point1Y = float.Parse(input.Substring(0, spaceIndex));

            // move along string and extract point 2 x
            input = input.Substring(spaceIndex + 1);
            spaceIndex = input.IndexOf(' ');
            point2X = float.Parse(input.Substring(0, spaceIndex));

            // point 2 y is the rest of the string
            input = input.Substring(spaceIndex + 1);
            point2Y = float.Parse(input);

            #region Unfortunately, Mono doesn't have a Split method!
            //string[] values = input.Split(' ');
            //point1X = float.Parse(values[0]);
            //point1Y = float.Parse(values[1]);
            //point2X = float.Parse(values[2]);
            //point2Y = float.Parse(values[3]);
            #endregion
        }
    }
}

核心问题修正与说明 #

• 避免覆盖全局变量：你在Main里定义的局部point1X、point2X等变量会覆盖类级别的全局变量，导致输入解析的坐标完全失效。直接使用类中已声明的全局变量即可。
• 距离计算修复：原代码中距离公式的第二项错误使用了point2Y - point1X，正确应为point2Y - point1Y，标准距离公式为：

  float distance = (float)Math.Sqrt(Math.Pow(point2X - point1X, 2) + Math.Pow(point2Y - point1Y, 2));
  

• 旋转角度计算修正：
  • Math.Atan2的参数顺序是(y差值, x差值)，对应游戏中从点1到点2的方向向量，正确调用应为：

    float radians = (float)Math.Atan2(point2Y - point1Y, point2X - point1X);
    

  • 如果课程要求输出角度而非弧度，需要转换：

    float degrees = radians * 180f / (float)Math.PI;
    

  • 注意游戏坐标系的方向（比如0度是否朝右、旋转方向正负），如果结果和预期相反，可能需要调整符号或加偏移量（如360 - degrees）。
• 清理冗余代码：删除硬编码的测试变量（如deltaX、angle2）和无意义的计算变量（如hypotnuse、CumulationofDistanceandHyp），只保留作业要求的计算逻辑。
• 输出规范：按照作业要求输出距离和角度即可，避免冗余输出内容。

修正后的核心代码片段 #

// 计算两点间距离
float distance = (float)Math.Sqrt(Math.Pow(point2X - point1X, 2) + Math.Pow(point2Y - point1Y, 2));

// 计算旋转角度（弧度转角度）
float angleRadians = (float)Math.Atan2(point2Y - point1Y, point2X - point1X);
float angleDegrees = angleRadians * 180f / (float)Math.PI;

// 按要求输出
Console.WriteLine($"{distance:F2} and {angleDegrees:F2}");

内容的提问来源于stack exchange，提问作者theUnderminer