Python中将字符串转换为项目符号列表的实现方法

1. 基于现有循环代码修改 #

在你已有的代码基础上，只需要修改append操作，给每个列表项开头加上* 前缀即可：

text = '''Lists of animals
Lists of aquarium life
Lists of biologists by author abbreviation
Lists of cultivars'''

lines = text.split('\n')
textList = []
for x in lines:
    textList.append(f'* {x}')  # 核心：给每行添加项目符号前缀

# 拼接成目标格式的字符串
final_output = '\n'.join(textList)
print(final_output)

2. 列表推导式简化实现 #

用列表推导式可以省略冗余的循环初始化代码，一步完成分割和前缀添加：

text = '''Lists of animals
Lists of aquarium life
Lists of biologists by author abbreviation
Lists of cultivars'''

textList = [f'* {line}' for line in text.split('\n')]
final_output = '\n'.join(textList)
print(final_output)

3. 正则表达式直接处理字符串 #

如果不想通过列表中转，可借助正则的多行匹配功能，直接给每行开头插入项目符号：

import re

text = '''Lists of animals
Lists of aquarium life
Lists of biologists by author abbreviation
Lists of cultivars'''

final_output = re.sub(r'^', '* ', text, flags=re.M)
print(final_output)

最终输出结果 #

以上三种方法都会生成符合要求的格式：

* Lists of animals
* Lists of aquarium life
* Lists of biologists by author abbreviation
* Lists of cultivars

内容的提问来源于stack exchange，提问作者Moses Ighedo