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如何通过Poetry钩子在package时用PyInstaller生成二进制可执行文件?

解决方案

一、修复builddist脚本配置无效问题

Poetry的scripts字段不支持直接写入完整Shell命令字符串,需改用以下两种方式之一:

方式1:数组形式指定命令(Poetry 1.2+ 支持)

修改pyproject.toml中的[tool.poetry.scripts]:

[tool.poetry.scripts]
start = "main:start"
builddist = ["poetry", "run", "pyinstaller", "main.py", "--collect-submodules", "application", "--onefile", "--name", "myapi"]

执行poetry run builddist即可触发PyInstaller构建。

方式2:Python包装函数

  1. 在项目根目录创建build_scripts.py文件:
import subprocess

def builddist():
    subprocess.run(
        [
            "pyinstaller",
            "main.py",
            "--collect-submodules", "application",
            "--onefile",
            "--name", "myapi"
        ],
        check=True,
        text=True
    )
  1. 修改pyproject.toml的脚本配置:
[tool.poetry.scripts]
start = "main:start"
builddist = "build_scripts:builddist"

执行poetry run builddist即可完成构建。

二、让poetry package自动生成可执行文件

通过自定义Poetry构建钩子,在执行包构建前自动触发PyInstaller命令:

  1. 在项目根目录创建build.py文件:
from poetry.core.masonry.builders.sdist import SdistBuilder
from poetry.core.masonry.builders.wheel import WheelBuilder
import subprocess

def pre_build_hook(original_build):
    def wrapper(self, *args, **kwargs):
        # 执行PyInstaller构建
        subprocess.run(
            [
                "pyinstaller",
                "main.py",
                "--collect-submodules", "application",
                "--onefile",
                "--name", "myapi"
            ],
            check=True,
            text=True
        )
        # 执行原有的构建逻辑
        return original_build(self, *args, **kwargs)
    return wrapper

# 为源码包和Wheel包构建注册前置钩子
SdistBuilder.build = pre_build_hook(SdistBuilder.build)
WheelBuilder.build = pre_build_hook(WheelBuilder.build)
  1. 确保pyproject.toml的构建系统配置不变:
[build-system]
requires = ["poetry-core"]
build-backend = "poetry.core.masonry.api"

现在执行poetry package时,会先自动生成PyInstaller可执行文件,再完成Python包的构建,产物均会输出到dist/目录下。

内容的提问来源于stack exchange,提问作者Rob Audenaerde

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最近更新时间:2026.07.23 04:27:28