如何用正则表达式提取含嵌套方括号字符串中的目标内容？

Got it, let's break down why your original regex isn't working and fix it. Your pattern \[.*?\] uses a non-greedy match, which stops at the first closing bracket it finds—this is the inner ] from [0], hence the partial results like [Test.A[0.

Here are a few solid solutions to extract exactly Test.A[0], Test.B[0], etc.:

Solution 1: Directly Match the Target Pattern #

If you know your target strings follow the format Test.[Letter][Number], you can skip dealing with the outer brackets entirely and match the exact pattern:

Test\.\w+\[\d+\]

• Test\.: Matches the literal "Test." (the backslash escapes the dot, which otherwise acts as a wildcard)
• \w+: Matches one or more word characters (covers letters like A/B/C/D)
• \[\d+\]: Matches [ followed by one or more digits, then ]

This regex will directly find all occurrences of your desired strings without needing to parse the outer brackets.

Solution 2: Extract Content from Outer Brackets #

If you want to pull whatever is inside the outer square brackets (regardless of the prefix, as long as there's no ' inside), use this regex with a capture group:

\[([^']+)\]

• \[: Matches the opening outer bracket
• ([^']+): Capture group that matches any character except ' (since your outer brackets are always followed by ' in the input)
• \]: Matches the closing outer bracket

The capture group will give you exactly the content inside each outer bracket pair (e.g., Test.A[0] from '[Test.A[0]]').

Solution 3: Exact Match for Your Specific Format #

For a regex tightly tailored to your input structure:

\[(Test\.[A-Z]\[\d\])\]

• \[(...)\]: Captures everything inside the outer brackets
• Test\.: Matches "Test."
• [A-Z]: Matches a single uppercase letter (A-D in your example)
• \[\d\]: Matches [ followed by a single digit, then ]

Capture group 1 will return your desired strings perfectly.

Example Usage (Python) #

import re

input_str = "('[Test.A[0]]' <>'' OR '[Test.B[0]]' <>'' OR '[Test.C[0]]' <>'' OR '[Test.D[0]]' <> '')"

# Using Solution 1
matches = re.findall(r'Test\.\w+\[\d+\]', input_str)
print(matches)  # Output: ['Test.A[0]', 'Test.B[0]', 'Test.C[0]', 'Test.D[0]']

# Using Solution 2
matches = re.findall(r'\[([^']+)\]', input_str)
print(matches)  # Output: ['Test.A[0]', 'Test.B[0]', 'Test.C[0]', 'Test.D[0]']

内容的提问来源于stack exchange，提问作者Edward