Selenium筛选公寓列表问题：Pop操作无法移除目标广告元素

你的代码没删除广告的核心原因是判断逻辑错误：你用apartments[i].find_elements(By.CSS_SELECTOR, ".reinforcement")是在当前元素的子节点里找带.reinforcement类的元素，但广告元素本身同时拥有.placard和.reinforcement两个类，并非子元素带这个类，所以这个判断永远返回空列表，自然不会触发pop操作。

下面给两种可行的解决方法：

方法一：用CSS选择器直接过滤（推荐） #

直接通过CSS选择器排除带.reinforcement类的.placard元素，一步到位，不需要后续遍历删除，效率更高：

# 直接定位只带.placard、不带.reinforcement的元素
apartments = WebDriverWait(driver, 2).until(
    EC.presence_of_all_elements_located((By.CSS_SELECTOR, ".placard:not(.reinforcement)"))
)
print(len(apartments))
# 输出应为25，已过滤掉广告

方法二：修正遍历判断逻辑 #

如果要保留先全选再过滤的逻辑，修改判断条件，检查元素自身的class属性是否包含reinforcement：

# Wait for the first page of listings to load
apartmentsTOBEDELETED = WebDriverWait(driver, 2).until(EC.presence_of_all_elements_located((By.CSS_SELECTOR, ".reinforcement")))
print(len(apartmentsTOBEDELETED))
# output is 1 .reinforcement ad

apartments = WebDriverWait(driver, 2).until(EC.presence_of_all_elements_located((By.CSS_SELECTOR, ".placard")))
print(len(apartments))
# output is 26, including one "apartment" (the ad) with the ".placard" and ".reinforcement" CSS tag

# 修改判断逻辑：检查元素自身的class是否包含reinforcement
i = 0
while i < len(apartments):
    # 获取元素的class属性，判断是否包含目标类
    if "reinforcement" in apartments[i].get_attribute("class"):
        print("found the element TO BE DELETED")
        apartments.pop(i)
    else:
        i += 1

# Print the number of apartments in the filtered list
print(len(apartments))
# 输出应为25，广告已被删除

内容的提问来源于stack exchange，提问作者tastyturban