如何使用discord.py在斜杠命令中发送文件？

我已经基于discord.py写了一个带掷骰子斜杠命令的Discord机器人，代码如下：

import discord
from discord import app_commands
from discord.ext import commands
import random

TOKEN = "" # 我的机器人令牌

bot = commands.Bot(command_prefix = "/", intents = discord.Intents.all())

@bot.event
async def on_ready():
    print("Bot is Up and Ready!")
    try:
        synced = await bot.tree.sync()
        print(f"Synced {len(synced)} command(s)!")
    except Exception as e:
        print(e)

@bot.tree.command(name = "roll", description = "roll a dice!")
async def roll(interaction: discord.Interaction):
    await interaction.response.send_message(f"`{random.randint(1, 6)}`")

现在我想在名为song的斜杠命令中发送根目录下的song.mp3文件，实现类似手动拖拽文件到Discord聊天框的效果，预期代码结构如下：

@bot.tree.command(name = "song", description = "send the song")
async def song(interaction: discord.Interaction):
    await interaction.response.send_message(f"{the_song_file}")

请问该如何实现这一功能？

要实现发送本地音频文件的效果，你需要使用discord.File类包装本地文件，再通过send_message方法的file参数传递这个文件对象，无需用字符串格式化的方式。

修改后的完整代码如下：

import discord
from discord import app_commands
from discord.ext import commands
import random

TOKEN = "" # 我的机器人令牌

bot = commands.Bot(command_prefix = "/", intents = discord.Intents.all())

@bot.event
async def on_ready():
    print("Bot is Up and Ready!")
    try:
        synced = await bot.tree.sync()
        print(f"Synced {len(synced)} command(s)!")
    except Exception as e:
        print(e)

@bot.tree.command(name = "roll", description = "roll a dice!")
async def roll(interaction: discord.Interaction):
    await interaction.response.send_message(f"`{random.randint(1, 6)}`")

@bot.tree.command(name = "song", description = "send the song")
async def song(interaction: discord.Interaction):
    # 创建discord.File对象，传入本地文件路径
    song_file = discord.File("song.mp3")
    # 发送消息时附带文件
    await interaction.response.send_message(file=song_file)

关键说明： #

• discord.File("song.mp3")会读取根目录下的song.mp3文件，生成Discord可识别的文件对象。
• 在send_message中通过file参数传递该对象，即可实现和手动拖拽上传相同的效果。
• 如果需要同时发送文字内容，可添加content参数，示例：await interaction.response.send_message(content="这是你要的音频！", file=song_file)

内容的提问来源于stack exchange，提问作者Coding_Guy