如何从URL与文件名拼接的字符串中提取附件的文件名与URL？

问题出在URL与下一个文件名无分隔拼接，可利用URL中name=参数值与对应文件名完全一致的特点，编写精准正则来匹配每个文件项：

import re

description = "----------------------------------------------\n\nTest Customer, May 11, 2023, 18:27\n\nDo you want to hear a construction joke? Oh, never mind, I'm still working on it!\n\nAttachment(s):\nistockphoto-1131743616-612x612.jpg - https://aaa.zendesk.com/attachments/token/jIUzlZ4ylKke4iP0kB/?name=istockphoto-1131743616-612x612.jpgzendesk_tickets_20230511_091412058891.json - https://aaa.zendesk.com/attachments/token/jIUzlZ4ylKke4iP0kB/?name=zendesk_tickets_20230511_091412058891.json"

# 提取附件区域
attachment_section = re.search(r'Attachment\(s\):\n(.+)', description, re.DOTALL).group(1)

# 利用URL的name参数与文件名一致的规则，匹配每个文件项
attachments = re.findall(r'([a-zA-Z0-9_-]+\.(jpg|json))\s-\s(https://.*?name=\1)', attachment_section)

# 整理结果
attachment_urls = []
for match in attachments:
    file_name = match[0]
    url = match[2]
    attachment_urls.append({
        'file_name': file_name,
        'url': url
    })

# 输出结果
for attachment in attachment_urls:
    print(f"File Name: {attachment['file_name']}")
    print(f"URL: {attachment['url']}")
    print()

代码说明 #

1. 正则([a-zA-Z0-9_-]+\.(jpg|json))\s-\s(https://.*?name=\1)的核心逻辑：
   • 捕获第一个分组：匹配以.jpg或.json结尾的文件名
   • 匹配-分隔符
   • 捕获第三个分组：匹配URL，利用\1反向引用确保URL中name=的参数值与前面捕获的文件名完全一致，自动截断拼接的多余内容
2. 该正则支持任意数量的附件，只要每个附件的URL都符合name=对应文件名的格式即可。

运行结果 #

File Name: istockphoto-1131743616-612x612.jpg
URL: https://aaa.zendesk.com/attachments/token/jIUzlZ4ylKke4iP0kB/?name=istockphoto-1131743616-612x612.jpg

File Name: zendesk_tickets_20230511_091412058891.json
URL: https://aaa.zendesk.com/attachments/token/jIUzlZ4ylKke4iP0kB/?name=zendesk_tickets_20230511_091412058891.json

内容的提问来源于stack exchange，提问作者スーパーマン