如何让Pydantic StrictFloat对float("nan")抛出验证错误?
解决Pydantic StrictFloat允许NaN的验证问题
Pydantic的StrictFloat默认会将float("nan")视为合法的float类型,因此不会触发验证错误。要实现拦截NaN的需求,最简方案是添加自定义验证逻辑,以下分版本给出具体实现:
方法一:字段验证器(Pydantic v2,最简改动)
直接给模型添加field_validator,检查列表中的每个元素是否为NaN:
from typing import List, Union from pydantic import BaseModel, StrictFloat, StrictInt, field_validator import math class StrictNumbers(BaseModel): values: List[Union[StrictFloat, StrictInt]] @field_validator('values', mode='after', each_item=True) def reject_nan(cls, item): if isinstance(item, float) and math.isnan(item): raise ValueError("不允许使用NaN值") return item # 此时会抛出验证错误 my_model = StrictNumbers(values=[1, 2.0, float("nan")])
方法二:自定义无NaN严格浮点类型(复用场景)
如果多个字段需要拦截NaN,可以自定义继承自StrictFloat的类型,内置NaN检查逻辑:
from typing import List, Union from pydantic import BaseModel, StrictFloat, StrictInt, GetCoreSchemaHandler from pydantic_core import core_schema import math class NonNanStrictFloat(StrictFloat): @classmethod def __get_pydantic_core_schema__(cls, source_type, handler: GetCoreSchemaHandler) -> core_schema.CoreSchema: base_schema = handler(source_type) return core_schema.no_info_before_validator_function( lambda x: x if not math.isnan(x) else ValueError("NaN值不被允许"), base_schema ) class StrictNumbers(BaseModel): values: List[Union[NonNanStrictFloat, StrictInt]] # 触发验证错误 my_model = StrictNumbers(values=[1, 2.0, float("nan")])
Pydantic v1 兼容方案
若使用Pydantic v1,改用validator装饰器实现:
from typing import List, Union from pydantic import BaseModel, StrictFloat, StrictInt, validator import math class StrictNumbers(BaseModel): values: List[Union[StrictFloat, StrictInt]] @validator('values', each_item=True) def reject_nan(cls, item): if isinstance(item, float) and math.isnan(item): raise ValueError("不允许使用NaN值") return item # 触发验证错误 my_model = StrictNumbers(values=[1, 2.0, float("nan")])
最简选择
仅针对当前模型的单个字段验证时,直接添加field_validator(v2)或validator(v1)是代码改动最小的方案。
内容的提问来源于stack exchange,提问作者Cord Kaldemeyer
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