如何检测Oculus控制器按键的触摸(未按压)状态?
Great question! I’ve run into this exact need when building interactions with Oculus Integration in Unity, so let me walk you through how to detect those touch-only states.
Oculus Integration’s OVRInput class provides dedicated methods and enumerations specifically for tracking touch (not just press) events on controller buttons. Here’s what you need to know:
1. Check Current Touch State with RawTouch
To verify if a button is being touched without being pressed, replace the RawButton enum with RawTouch in your OVRInput.Get() call. For your example with the B button:
// Check if the B button is currently touched (no press required) bool isBTouched = OVRInput.Get(OVRInput.RawTouch.B); Debug.Log($"B button touched: {isBTouched}");
2. Track Touch Start/End Events
Just like with press actions, you can capture the exact moment a touch begins or ends using GetDown() and GetUp() paired with RawTouch:
// Detect the first frame the B button is touched if (OVRInput.GetDown(OVRInput.RawTouch.B)) { Debug.Log("B button was just touched"); } // Detect the first frame the B button stops being touched if (OVRInput.GetUp(OVRInput.RawTouch.B)) { Debug.Log("B button was released from touch"); }
3. Supported Touch-Sensitive Inputs
The RawTouch enum covers all touch-capable controls on Oculus controllers, including:
- Face buttons:
RawTouch.A,RawTouch.B,RawTouch.X,RawTouch.Y - Triggers:
RawTouch.LIndexTrigger,RawTouch.RIndexTrigger - Joysticks:
RawTouch.LThumbstick,RawTouch.RThumbstick
Bonus: Controller-Agnostic Touch Detection
If you want to build interactions that work across different Oculus controller models (without hardcoding button names), use the non-raw OVRInput.Touch enum:
// Check if the user's primary interaction button is touched bool isPrimaryButtonTouched = OVRInput.Get(OVRInput.Touch.PrimaryButton);
This aligns with how the Oculus hand animation system works—it uses these touch state signals to update hand poses, so detecting them directly lets you replicate or extend that behavior in your own code.
内容的提问来源于stack exchange,提问作者Jian

