如何实现Python猜单词功能：错误输入则重启6次循环流程？

你的需求是：目标单词flower有6个字母，最多允许6次猜词尝试，每次猜词错误就重新展示提示并让用户再次输入，直到猜对或用完次数。以下是修改后的代码及说明：

修改后的完整代码 #

word = 'flower'
max_attempts = len(word)  # 最多6次尝试
attempts = 0

while attempts < max_attempts:
    # 打印下划线提示
    print("\nHint : ")
    print('_' * len(word))
    print()
    
    # 获取用户猜词，先校验长度
    guess = input('What is your guess? ')
    while len(guess) != len(word):
        guess = input('Please enter a word of correct length: ')
    
    # 检查猜词是否完全正确
    if guess.lower() == word.lower():
        print(f"\nCorrect! You guessed it in {attempts + 1} attempts.")
        break
    
    # 逐字符对比并展示结果
    count = 0
    result = []
    while count < len(word):
        if guess[count].lower() not in word:
            result.append('_')
        elif guess[count].lower() == word[count]:
            result.append(guess[count].upper())
        else:
            result.append(guess[count].lower())
        count += 1
    print(''.join(result))
    
    attempts += 1

# 用完所有次数仍未猜对的情况
if attempts == max_attempts:
    print(f"\nYou've used all {max_attempts} attempts. The correct word was '{word}'.")

关键改动说明 #

• 外层循环控制尝试次数：用while attempts < max_attempts确保最多运行6次
• 每次尝试前重新打印下划线提示，符合"错误输入则重启整个流程"的要求
• 增加了猜词完全正确的判断逻辑，猜对后直接结束游戏
• 修复了原代码中count变量仅在else分支递增的bug，现在每个循环都会正确更新count
• 用列表收集结果再拼接打印，比逐字符打印更清晰易读
• 补充了用完所有尝试次数的提示信息

内容的提问来源于stack exchange，提问作者HARISH S