Python天气与列车状态判断代码始终输出else，如何修复？

你的代码核心问题是输入类型不匹配：input()函数返回的是字符串类型，但你在条件判断里把它和布尔值True/False做比较，这两者永远不会相等，所以无论输入什么，所有条件分支都不满足，最终只会执行else。

比如你输入"False"，变量raining实际是字符串"False"，而"False" == False的结果是False，第一个if条件不成立，后续elif也都不满足，只能走到else分支。

方案1：将输入转换为布尔值 #

通过判断输入的字符串内容，把它转换成对应的布尔值，同时用strip()处理输入前后的空格，避免用户不小心输入空格导致的错误：

raining_input = input("Will it be raining tomorrow? Please enter True or False: ").strip()
# 只有输入"True"时，raining才为True，其他情况（包括输入"False"）都为False
raining = raining_input == "True"
trainOnTime = input("Will the train be on time? Please enter Yes, Early or Late: ").strip()

if not raining and trainOnTime == "Yes":
    print("The train is on time you can walk to the train station.")
elif not raining and trainOnTime == "Early":
    print("The train is early you will have to drive to the train station.")
elif raining and trainOnTime == "Late":
    print("It is raining and the train will be late, you will have to drive to work!", str(raining), str(trainOnTime))
else:
    print("Invalid entry, please try again!")
input('Press ENTER to exit')

方案2：直接比较字符串 #

把条件判断里的布尔值True/False改成对应的字符串"True"/"False"，直接和输入的字符串做比较：

raining = input("Will it be raining tomorrow? Please enter True or False: ").strip()
trainOnTime = input("Will the train be on time? Please enter Yes, Early or Late: ").strip()

if raining == "False" and trainOnTime == "Yes":
    print("The train is on time you can walk to the train station.")
elif raining == "False" and trainOnTime == "Early":
    print("The train is early you will have to drive to the train station.")
elif raining == "True" and trainOnTime == "Late":
    print("It is raining and the train will be late, you will have to drive to work!", raining, trainOnTime)
else:
    print("Invalid entry, please try again!")
input('Press ENTER to exit')

建议加上strip()处理输入，避免用户输入时不小心带了空格（比如" False "）导致判断失败，这样程序的容错性会更好。

内容的提问来源于stack exchange，提问作者CJDev2013